C++程序是否在I/EL语句中有一个转换语句

我试图在if/else语句中执行switch语句。它不起作用。我不确定这是否是因为我在switch语句中使用的保留字break使我退出了函数。请帮忙

    /*  Date : March 3, 2015
    Date Due : March 23, 2015
    Program Name: Hospital Calculator
    Description: This program will ask the user to enter several information 
    related to his/her room floor measurements. After that, it will generate 
    a bill that will tell the customer the price for the carpet job.
    */

  #include <iostream>
  #include <iomanip>
  #include <string>
  #include <cmath>
  #include <cctype>

  //Constants
              // Room Rates
  const float SINGLE_ROOM    = 525.00,
              DOUBLE_ROOM    = 325.00,
              WARD           = 550.00,
              //Phone Access Rates
              SHARED_LINE    = 2.95,
              DEDICATED_LINE = 5.95,
              //Television Rates
              BASIC_CHANNELS = 2.95,
              CABLE_CHANNELS = 5.95;

  using namespace std;

    //Prototypes
  void getdata(string &, int &);
  float get_room ( int,  string &);
  float get_phone(int days, string &);  


  int main()
  {
     string name,
            room_type,
            phone_type,
            tv_type;

     int   days;

    float room_charges,
          phone_charges,
          tv_charges;

    //The ones below are subfuntions calls that devide each section    

  //Input section (call)
    getdata(name,days);
  //room_charges = 
  //room_charges = get_room(days,room_type);
  phone_charges = get_phone(days, phone_type);
  cout << phone_charges << endl;
  cout << phone_type << endl;

  /*tv_charges = get_tv(days, tv_type);
  print(name, days, room_charges, phone_charges, tv_charges);
  */

    cin.get();
    cin.ignore();
    return 0;
  }

  // Input Section
  //This function takes the information needed from the user
  void getdata(string & name, int & days)
  {
    string symbol;

    symbol.assign (50, '*');
    cout << symbol<< endl;
    cout << right << setw(22) << "\tCustomer's Name\t\t\t: ";
    getline (cin,name);
    cout << right << setw(22) << "\tNumber of days in the hospital\t\t: ";
    cin >> days;
    cout << symbol << endl; 
    cin.ignore();
  }

  float get_room ( int days, string & room_type)  
  {
      string choice;
      char   ch;
      float  room_charges;
      cout << "\n\n\t\t\tRoom Used\n";
      cout <<     "\t\t\t________\n\n";
      cout << fixed << setprecision (2);
      cout << "\t1- Single room-One bed \t"<< SINGLE_ROOM <<"\n\n";
      cout << "\t2- Double room-Two beds\t"<< DOUBLE_ROOM <<"\n\n";
      cout << "\t3- Ward                \t"<< WARD <<"\n\n";
      cout << "\t   Enter Choice 1, 2, or 3 : ";
      getline(cin, choice); 
      cin.ignore();
      ch = toupper(choice[0]);

      if (ch == '1' or ch == 'S')
         { 
            room_charges = SINGLE_ROOM * days;
            room_type    = "in a Single Room";
         }

      else if (ch == '2' or ch == 'D')
        { 
            room_charges = DOUBLE_ROOM * days;
            room_type    = "in a Double Room";
         }

      else if (ch == '3' or ch == 'W')
        {
            room_charges = WARD * days;
            room_type    = "in a Ward";
        }



      return room_charges;

  }

   float get_phone(int days, string & phone_type)

  {  
      string prompt,
             choice;
      char   pr, ch;
      float  phone_charges;
      cout << "Would you like Phone Access (Y/N): ";
      cin >> prompt;
      pr = toupper(prompt[0]);

      if (pr == 'Y') 
      {
          cout << "\n\n\t\t\tPhone Access\n";
          cout <<     "\t\t\t________\n\n";
          cout << "\t1- Shared   \t" << SHARED_LINE <<"\n\n";
          cout << "\t2- Dedicated\t"<< DEDICATED_LINE <<"\n\n";
          cout << "\t   Enter Choice 1 or 2: ";
          getline(cin, choice); 

          ch = toupper(choice[0]);

          if (ch == '1' or ch == 'S')
           { 
               phone_charges = (SHARED_LINE * days);
               phone_type    = "(Shared)";

           else if (ch == '2' or ch == 'D')     
             case '2':
             case 'D':        
              {
               phone_charges = (DEDICATED_LINE * days);
               phone_type    = "(Cable)";
               break;
              }  


           }


      }    

        else if (pr == 'N')
        {
          phone_charges = 0.00;
          phone_type = "None";
        }

         cin.ignore();
          return phone_charges;  

     }

---

这里不需要switch语句。但为了保持现有的功能，这里有一些修复方法。您缺少几个括号，开关本身也丢失了

---

您没有使用关键字“switch”。代码应该如下所示

else if(ch == '2' or ch == 'D'){
    switch(ch){
    case '2':
        break;
    case 'D':
         phone_charges = (DEDICATED_LINE * days);
         phone_type    = "(Cable)";
         break;
    }
}

---

我不确定您是否打算将“2”的案例留空，但每个案例中没有中断都会导致失败。

您真的不能将其简化为一个简单的代码示例来说明问题吗？帮助我们帮助您。我在您的代码中看不到switch语句，只有一些case语句。它们需要在交换机中使用。嗯，在if/else中没有交换机。在if中有一些switch-case项，我认为它会给您一个编译错误。switch语句通常以关键字switch…开头。。。。。。。具体地说，在if ch='2'| | ch='D'之后是一个开关ch{。如果你正确地做了这个开关，你可以将它放在if/else块中。这会使它编译，但我怀疑代码应该是这样的！当我说应该时，我是专门针对“switch case”构造的。

else if(ch == '2' or ch == 'D'){
    switch(ch){
    case '2':
        break;
    case 'D':
         phone_charges = (DEDICATED_LINE * days);
         phone_type    = "(Cable)";
         break;
    }
}