删除重复字符并将其放在c++； 我试图在C++中添加标题，但没弄清楚。 这是我试过的 char *str=new char[100]; cout<<"enter the string"; cin.getline(str,100); int len=strlen(str); int i=0; //iterating through the string while(i<len-1) { int signal=0; char x; int j=i+1; while(j<len) { if(str[j]==str[i]) { x=str[i]; for(int k=j;k<len;k++) { str[k]=str[k+1]; } len--; signal=1; } else { j++; } } if(signal==1) { for(int l=i;l<len;l++) { str[l]=str[l+1]; } str[len-1]=x; } } cout<<str; char*str=新字符[100]； cout

使用std:：string更容易：

     std::string input("Darren");
     std::string uniqueCharsString, repeatedCharsString;

     for (int i = 0; i < input.length(); ++i)
     {
        // If we are looking at the last character, we need to compare it with the previous one
        if (i == input.length() - 1)
        {
           // If the character is the same as the previous one, add it to the repeatedCharsString
           if (input.at(i) == input.at(i-1))
              repeatedCharsString.push_back(input.at(i));
           // If the character is not the same as the previous one, add it to the uniqueCharsString
           else
              uniqueCharsString.push_back(input.at(i));
        }
        // If the character is the same as the following one, add it to the repeatedCharsString
        else if (input.at(i) == input.at(i+1))
        {
           repeatedCharsString.push_back(input.at(i));
           // Skip the next character since we already know it's the same as the previous one
           i++;
        }
        // If the character is not the same as the following one, add it to the uniqueCharsString
        else
           uniqueCharsString.push_back(input.at(i));
     }
     std::string result(uniqueCharsString + repeatedCharsString);

std:：字符串输入（“Darren”）；
std:：字符串uniqueCharsString，repeatedCharsString；
对于（int i=0；i

字符串比较区分大小写

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希望这有帮助

重复字符是什么意思？具有相同值的两个连续字符？以前已出现在字符串中任何位置的字符？你需要保留它们吗？你需要保持这些字符串的相对位置吗？@chris它会对功能进行任何更改吗？@bhawin，它很好地集成到C字符串中，而且绝对更安全、更简单。@david例如，“darren”是输入字符串，而“daenr”应该是output@bhawin：路演怎么样？这会保持原样，还是转变成“拉德什沃”？花点时间完整地说明问题，并举例说明任何潜在用途。