C++ 如何在EcliSpeIDE中使用OpenSound库OpenAL(freealut)?
我使用以下命令成功安装了OpenAL:C++ 如何在EcliSpeIDE中使用OpenSound库OpenAL(freealut)?,c++,audio,openal,C++,Audio,Openal,我使用以下命令成功安装了OpenAL: yum install freealut freealut-devel 但是,在这个问题之后,我添加了一些C++代码来处理下面的库: #include <AL/al.h> #include <AL/alc.h> #include <AL/alut.h> void init_al() { ALCdevice *dev = NULL; A
yum install freealut freealut-devel
但是,在这个问题之后,我添加了一些C++代码来处理下面的库:
#include <AL/al.h>
#include <AL/alc.h>
#include <AL/alut.h>
void init_al()
{
ALCdevice *dev = NULL;
ALCcontext *ctx = NULL;
const char *defname = alcGetString(NULL, ALC_DEFAULT_DEVICE_SPECIFIER);
std::cout << "Default device: " << defname << std::endl;
dev = alcOpenDevice(defname);
ctx = alcCreateContext(dev, NULL);
alcMakeContextCurrent(ctx);
alGenBuffers(1, &buf);
/* Fill buffer with Sine-Wave */
freq = 1440.f;
seconds = 0.2;
sample_rate = 22050;
buf_size = 6000;
samples = new short[buf_size];
for(int i=0; i<buf_size; ++i) {
samples[i] = 32760 * sin( (2.f*float(M_PI)*freq)/sample_rate * i );
}
/* Download buffer to OpenAL */
alBufferData(buf, AL_FORMAT_MONO16, samples, buf_size, sample_rate);
/* Set-up sound source and play buffer */
src = 0;
alGenSources(1, &src);
alSourcei(src, AL_BUFFER, buf);
alGenBuffers(1, &buf);
/* Fill buffer with Sine-Wave */
freq = 1000.f;
seconds = 0.2;
sample_rate = 22050;
buf_size = 12000;
samples = new short[buf_size];
float add=1;
for(int i=0; i<buf_size; ++i) {
samples[i] = 32760 * sin( (2.f*float(M_PI)*freq)/sample_rate * i );
}
/* Download buffer to OpenAL */
alBufferData(buf, AL_FORMAT_MONO16, samples, buf_size, sample_rate);
/* Set-up sound source and play buffer */
src2 = 0;
alGenSources(1, &src2);
alSourcei(src2, AL_BUFFER, buf);
}
#包括
#包括
#包括
void init_al()
{
ALCdevice*dev=NULL;
ALCcontext*ctx=NULL;
const char*defname=alcGetString(空,ALC\u默认\u设备\u说明符);
std::cout这些是标准的openal头文件-不确定为什么要使用alut或freealut
#include <AL/al.h>
#include <AL/alc.h>
// #include <OpenAL/al.h> // apple only
// #include <OpenAL/alc.h> // apple only
因此,它的编译行标志将是-l,后跟in-lalut标志
您提供的代码不完整-它缺少许多var定义,因此无法在我的末尾编译
alut
or maybe freealut