C++ 我在函数中声明了n，但在我编译代码并尝试运行之后，它给了我n是未识别的错误

以下是简单的语法错误：

Error   1   error C2039: 'print_out' : is not a member of '`global namespace''  
Error   2   error C2065: 'n' : undeclared identifier    
Error   3   error C2448: 'print_out' : function-style initializer appears to be a function definition   
    4   IntelliSense: identifier "n" is undefined   
    5   IntelliSense: identifier "n" is undefined   

---

修复这些问题并编译：

您应该像这样声明您的函数：

// void::print_out(int n); //// :: is the scope operator.
vpid print_out(int n);

// int print_out(n) {  //// the type must still be there.
void print_out(int n) {

并且应使用与标题相同的返回类型定义：

void print_out(int); //Takes an int argument, and 'void' specifies it has no return value

---

它应该是int print_outit n，main中的参数和变量是两个独立的实体。这给了我一个错误：不能重载仅由返回类型区分的函数。当我加入for循环时，它必须是一个空白，它要求我这样做。它说打印输出函数应该有类型void；它不返回值。

void print_out(int); //Takes an int argument, and 'void' specifies it has no return value

void print_out(int n) { //is a 'void' type function as previously declared
    for (int i = 1; i <= n; i++)     //We can declare 'i' in the for loop like this
        cout << i << " ";    
    //Note we're not returning a value: It's a 'void' function.
}