C++ 在OpenCV中使用地址消毒器

我正试图将谷歌的应用于CUDA项目，更准确地说是OpenCV CUDA功能。然而，我在第一次cuda呼叫时出现了“内存不足”错误

OpenCV Error: Gpu API call (out of memory) in getDevice, file opencv-2.4.11/src/opencv-2.4.11/modules/dynamicuda/include/opencv2/dynamicuda/dynamicuda.hpp, line 664
terminate called after throwing an instance of 'cv::Exception'
  what():  opencv-2.4.11/src/opencv-2.4.11/modules/dynamicuda/include/opencv2/dynamicuda/dynamicuda.hpp:664: error: (-217) out of memory in function getDevice

它可以用计算机复制

#include <opencv2/gpu/gpu.hpp>
int main()
{
  cv::gpu::printCudaDeviceInfo(cv::gpu::getDevice());
  return 0;
}

我在gcc中得到了相同的结果。 我还尝试将cuda函数列入黑名单，但没有结果

现在在不使用opencv的情况下使用cuda：

#include <cuda_runtime.h>
int main()
{
  int count = -1;
  cudaGetDevice(&count);
  cout << "Device count: " << count << endl;
  return 0;
}
clang++ -O1 -g -fsanitize=address -fsanitize-blacklist=asan.blacklist -stdlib=libstdc++ -lstdc++ -I/opt/cuda/include -L/opt/cuda/lib64 -lcudart  -o sanitizer sanitizer.cpp && ./sanitizer

#包括
int main（）
{
整数计数=-1；
CUDAGET设备（计数和计数）；
GitHub上的cout相关问题：
#include <cuda_runtime.h>
int main()
{
  int count = -1;
  cudaGetDevice(&count);
  cout << "Device count: " << count << endl;
  return 0;
}
clang++ -O1 -g -fsanitize=address -fsanitize-blacklist=asan.blacklist -stdlib=libstdc++ -lstdc++ -I/opt/cuda/include -L/opt/cuda/lib64 -lcudart  -o sanitizer sanitizer.cpp && ./sanitizer

=================================================================
==25344==ERROR: LeakSanitizer: detected memory leaks

Direct leak of 136 byte(s) in 1 object(s) allocated from:
    #0 0x4bc4a2  (/home/pluc/work/tests/sanitizer+0x4bc4a2)
    #1 0x7f71f0fa69ba  (<unknown module>)

SUMMARY: AddressSanitizer: 136 byte(s) leaked in 1 allocation(s).