使用C++;:未定义的引用错误 我想调用C++中的Haskell函数,并使用的教程

使用C++;:未定义的引用错误 我想调用C++中的Haskell函数,并使用的教程,c++,haskell,g++,ghc,ffi,C++,Haskell,G++,Ghc,Ffi,所以我有一个haskell文件Foo.hs: module Foo where foreign export ccall foo :: Int -> IO Int foo :: Int -> IO Int foo n = return (length (f n)) f :: Int -> [Int] f 0 = [] f n = n:(f (n-1)) 打电话 ghc Foo.hs 它创建了一个Foo_stub.h: #include "HsFFI.h" #ifdef

所以我有一个haskell文件Foo.hs:

module Foo where

foreign export ccall foo :: Int -> IO Int

foo :: Int -> IO Int
foo n = return (length (f n))

f :: Int -> [Int]
f 0 = []
f n = n:(f (n-1))
打电话

ghc Foo.hs
它创建了一个Foo_stub.h:

#include "HsFFI.h"
#ifdef __cplusplus
extern "C" {
#endif
extern HsInt foo(HsInt a1);
#ifdef __cplusplus
}
#endif
Foo_stub.c:

#define IN_STG_CODE 0
#include "Rts.h"
#include "Stg.h"
#ifdef __cplusplus
extern "C" {
#endif

extern StgClosure Foo_zdffoozualy_closure;
HsInt foo(HsInt a1)
{
Capability *cap;
HaskellObj ret;
HsInt cret;
cap = rts_lock();
cap=rts_evalIO(cap,rts_apply(cap,(HaskellObj)runIO_closure,rts_apply(cap, Foo_zdffoozualy_closure,rts_mkInt(cap,a1))) ,&ret);
rts_checkSchedStatus("foo",cap);
cret=rts_getInt(ret);
rts_unlock(cap);
return cret;
}
static void stginit_export_Foo_zdffoozualy() __attribute__((constructor));
static void stginit_export_Foo_zdffoozualy()
{getStablePtr((StgPtr) &Foo_zdffoozualy_closure);}
#ifdef __cplusplus
}
#endif
它还创建了一个Foo_stub.o文件

我现在创建了一个main.cpp文件:

#include "Foo_stub.h"
int main()
{
  foo(3);
}
并试图编译它

使用g++失败:

$ g++ -I/usr/lib/ghc-7.0.3/include/ main.cpp Foo_stub.o
Foo_stub.o: In function `foo':
Foo_stub.c:(.text+0xa): undefined reference to `rts_lock'
Foo_stub.c:(.text+0x18): undefined reference to `rts_mkInt'
Foo_stub.c:(.text+0x20): undefined reference to `Foo_zdffoozualy_closure'
Foo_stub.c:(.text+0x28): undefined reference to `rts_apply'
Foo_stub.c:(.text+0x30): undefined reference to `base_GHCziTopHandler_runIO_closure'
Foo_stub.c:(.text+0x38): undefined reference to `rts_apply'
Foo_stub.c:(.text+0x48): undefined reference to `rts_evalIO'
Foo_stub.c:(.text+0x58): undefined reference to `rts_checkSchedStatus'
Foo_stub.c:(.text+0x62): undefined reference to `rts_getInt'
Foo_stub.c:(.text+0x6d): undefined reference to `rts_unlock'
Foo_stub.o: In function `stginit_export_Foo_zdffoozualy':
Foo_stub.c:(.text+0x80): undefined reference to `Foo_zdffoozualy_closure'
Foo_stub.c:(.text+0x85): undefined reference to `getStablePtr'
collect2: ld returned status 1
所以我尝试了ghc——制造。但这也失败了:

$ ghc --make main.cpp Foo_stub.o
cc1plus: Warning: Option »-Wimplicit« is valid for C/ObjC, but not for C++ [activated by default]
Foo_stub.o: In function `foo':
Foo_stub.c:(.text+0x20): undefined reference to `Foo_zdffoozualy_closure'
Foo_stub.o: In function `stginit_export_Foo_zdffoozualy':
Foo_stub.c:(.text+0x80): undefined reference to `Foo_zdffoozualy_closure'
collect2: ld returned status 1
如何编译它?

试试以下方法:

$ ghc --make -no-hs-main main.cpp Foo.hs
我认为问题在于GHC认为您传递的存根对象文件只是另一个正常链接的对象,但您没有传递
Foo.o
文件本身,因此存根代码没有任何链接!直接传入源文件应该可以解决这个问题。(这只是基于文档和您看到的错误的推测,我还没有测试它。)

我想你可以像这样单独编译:

$ ghc --make Foo.hs
$ ghc --make -no-hs-main main.cpp Foo.o
但我不确定。您可能还需要考虑将Haskell代码构建成一个,然后通常使用
g++
将其链接到主程序

-如果程序的入口点不是Haskell值
main.main
,则不需要hs main
,如您链接的文档中所述