C++ 我需要显示最高和最低销售值

我需要创建一个程序，输入一周中每一天的每日销售额。输入值后，我需要能够显示：

Sales for day 1 are ###

Sales for day 2 are ###

The lowest sales was XXX

The highest sales was XXX

问题是我无法将我的代码设置为cout：

Sales for day 1 are XXX

Sales for day 2 are XXX

我能说的就是

Sales are:

XXX

XXX

XXX

我也不知道如何找到最低和最高的销售额。我们甚至还没有开始使用最小和最大函数，所以我不知道如何实现它

到目前为止，我的代码是：

const int DAYS_SALES = 7;
double sales[DAYS_SALES];
int sub;
double min = 0;
double max = 0;

for(sub = 0; sub < DAYS_SALES; ++sub)
{
    cout << "Enter in the sales for day " << (sub + 1) << " ";
    cin >> sales[sub];
}
cout << endl << "The sales for day are: " << endl;
for (sub = 0; sub < DAYS_SALES; ++sub)
    cout << sales[sub] << " " << endl;

const int DAYS\u SALES=7；
双倍销售额[天销售额]；
int sub；
双最小值=0；
双最大值=0；
对于（sub=0；sub当for循环遍历每个值时，cout跟踪最小值和最大值

如果当前值（
sales[sub]
）小于到目前为止的
min
，则将该值存储为新的最小值

const int DAYS_SALES = 7;
double sales[DAYS_SALES];
int sub;
double min = 0.0;
double max = 0.0;

for(sub = 0; sub < DAYS_SALES; ++sub)
{
    cout << "Enter in the sales for day " << (sub + 1) << " ";
    cin >> sales[sub];
}

min = sales[0];
max = sales[0];

cout << endl << "The sales for day are: " << endl;
for (sub = 0; sub < DAYS_SALES; ++sub)
{
    cout << endl << "The sales for day are: " << sales[sub] << " " << endl;

    if (sales[sub] < min)
    {   // If we find a smaller min. value, store that in min
        min = sales[sub];
    }

    if (sales[sub] > max)
    {   // If we find a bigger max. value, store that in max
        max = sales[sub];
    }
}

// Print out the Min and Max that we found.
cout<< "The lowest sales was " << min;
cout<< "The highest sales was " << max <<endl;

const int DAYS\u SALES=7；
双倍销售额[天销售额]；
int sub；
双最小值=0.0；
双最大值=0.0；
对于（sub=0；subcout好的，也许您应该将您的值输入到相应类型的
std:：vector
，然后在其上调用
std:：minmax（…）