C++ 如何将目录中具有完整路径的所有文件传递到execv中的参数数组?
我正在尝试读取给定目录中的所有文件(图片)并将其传递给execv。我想启动帧缓冲区图像查看器(fbi) 现在,当我从图片所在的目录启动它时,它就可以工作了。如何操作向量,使其不仅保存文件名,还保存路径+文件名C++ 如何将目录中具有完整路径的所有文件传递到execv中的参数数组?,c++,stdvector,execvp,C++,Stdvector,Execvp,我正在尝试读取给定目录中的所有文件(图片)并将其传递给execv。我想启动帧缓冲区图像查看器(fbi) 现在,当我从图片所在的目录启动它时,它就可以工作了。如何操作向量,使其不仅保存文件名,还保存路径+文件名 int startSlideshow (char* pathtoFBI) { pid_t fbiPid; fbiPid = fork(); if (fbiPid == 0) { /* this is the child process */ DIR *pictureDi
int startSlideshow (char* pathtoFBI) {
pid_t fbiPid;
fbiPid = fork();
if (fbiPid == 0) {
/* this is the child process */
DIR *pictureDirectory;
struct dirent *dir;
int i = 0;
vector<char*> argVector;
char pDirectory[] = "/home/pi/bilder/";
argVector.push_back(pathtoFBI); /* first Argument is Program name */
pictureDirectory = opendir(pDirectory);
if (pictureDirectory){
while ((dir = readdir(pictureDirectory)) != NULL) {
i++;
if (i > 2) { /* first element is "." second is ".." */
argVector.push_back(dir->d_name);
}
}
//i -= 2;
} else ERREXIT("reading picture directory");
closedir(pictureDirectory);
argVector.push_back(NULL);
char** fbiArgv = &argVector[0];
execvp(pathtoFBI, fbiArgv); /* pid is taken over by fbi */
_exit(EXIT_FAILURE);
}
int startSlideshow(char*pathtoFBI){
pid_t fbiPid;
fbiPid=fork();
如果(fbiPid==0){
/*这是子进程*/
目录*图片目录;
结构方向*dir;
int i=0;
向量argVector;
char pDirectory[]=“/home/pi/bilder/”;
argVector.push_back(pathtoFBI);/*第一个参数是程序名*/
pictureDirectory=opendir(PDdirectory);
if(图片目录){
while((dir=readdir(pictureDirectory))!=NULL){
i++;
如果(i>2){/*第一个元素是“.”,第二个元素是“.”*/
argVector.push_back(dir->d_name);
}
}
//i-=2;
}else ERREXIT(“读取图片目录”);
closedir(图片目录);
argVector.push_back(空);
字符**fbiArgv=&argVector[0];
执行副总裁(pathtoFBI,fbiArgv);/*pid由fbi接管*/
_退出(退出失败);
}
给定您的代码,您只需在每个文件名前添加PDdirectory:
--- c1.cc 2013-02-04 02:35:47.000000000 +0400
+++ c2.cc 2013-02-04 02:39:03.000000000 +0400
@@ -8,7 +8,7 @@
DIR *pictureDirectory;
struct dirent *dir;
int i = 0;
- vector<char*> argVector;
+ vector<char*> argVector; vector<string> fpVector;
char pDirectory[] = "/home/pi/bilder/";
argVector.push_back(pathtoFBI); /* first Argument is Program name */
pictureDirectory = opendir(pDirectory);
@@ -16,7 +16,8 @@
while ((dir = readdir(pictureDirectory)) != NULL) {
i++;
if (i > 2) { /* first element is "." second is ".." */
- argVector.push_back(dir->d_name);
+ fpVector.push_back(string(pDirectory) + dir->d_name);
+ argVector.push_back((char*) fpVector.back().c_str());
}
}
//i -= 2;
--c1.cc 2013-02-04 02:35:47.000000000+0400
+++c2.cc 2013-02-0402:39:03.000000000+0400
@@ -8,7 +8,7 @@
目录*图片目录;
结构方向*dir;
int i=0;
-向量argVector;
+向量argVector;向量fpVector;
char pDirectory[]=“/home/pi/bilder/”;
argVector.push_back(pathtoFBI);/*第一个参数是程序名*/
pictureDirectory=opendir(PDdirectory);
@@ -16,7 +16,8 @@
while((dir=readdir(pictureDirectory))!=NULL){
i++;
如果(i>2){/*第一个元素是“.”,第二个元素是“.”*/
-argVector.push_back(dir->d_name);
+fpVector.push_back(字符串(pddirectory)+dir->d_名称);
+argVector.push_back((char*)fpVector.back().c_str());
}
}
//i-=2;
更一般地说,还有Boost文件系统和。谢谢!这很好用。但是我用“string fpString”替换了“vector fpVector”,并在while循环中使用“fpString=string(pddirectory)+dir->d_name;'以避免有2个向量。您不应该这样做,因为execvp需要由字符串分配的cstring,如果您的字符串是临时的,那么cstring将挂起。