C++ 如何在asmjit中获取当前指令?

C++ 如何在asmjit中获取当前指令?,c++,asmjit,C++,Asmjit,据此,在x64中,您可以执行lea-rax、[rip]来获取当前指令。如何使用asmjit实现这一点?我找到了解决方案:assembler.lea(asmjit::x86::rax,asmjit::x86::ptr(asmjit::x86::rip))我找到了解决方案:assembler.lea(asmjit::x86::rax,asmjit::x86::ptr(asmjit::x86::rip))

据此,在x64中,您可以执行
lea-rax、[rip]
来获取当前指令。如何使用asmjit实现这一点?

我找到了解决方案:
assembler.lea(asmjit::x86::rax,asmjit::x86::ptr(asmjit::x86::rip))

我找到了解决方案:
assembler.lea(asmjit::x86::rax,asmjit::x86::ptr(asmjit::x86::rip))