C# c查找列表
如何提取字符串列表中常见的所有单词 例如:C# c查找列表,c#,string,list,linq,find,C#,String,List,Linq,Find,如何提取字符串列表中常见的所有单词 例如: //Output = Bammler GOV "Bammler Tokyo SA GOV" "Zurich Bammler GOV" "London Bammler 12 GOV" "New Bammler York GOV" 我尝试了以下几点: static void Main(string[] args) { List<string> MyStringList = new List<
//Output = Bammler GOV
"Bammler Tokyo SA GOV"
"Zurich Bammler GOV"
"London Bammler 12 GOV"
"New Bammler York GOV"
我尝试了以下几点:
static void Main(string[] args)
{
List<string> MyStringList = new List<string>()
{
"Bammler Tokyo SA GOV",
"Zurich Bammler GOV",
"London Bammler 12 GOV",
"New Bammler York GOV"
};
string shortest = MyStringList.OrderBy(s => s.Length).First();
IEnumerable<string> shortestSubstrings = getAllSubstrings(shortest).OrderByDescending(s => s.Length);
var other = MyStringList.Where(s => s != shortest).ToArray();
string longestCommonIntersection = string.Empty;
foreach (string subStr in shortestSubstrings)
{
bool allContains = other.All(s => s.Contains(subStr));
if (allContains)
{
longestCommonIntersection = subStr;
break;
}
}
}
public static IEnumerable<string> getAllSubstrings(string word)
{
return from charIndex1 in Enumerable.Range(0, word.Length)
from charIndex2 in Enumerable.Range(0, word.Length - charIndex1 + 1)
where charIndex2 >= 2
select word.Substring(charIndex1, charIndex2);
}
我在这里找到了这个,但这将仅提取例如Bammler。您可以从所有字符串中得到单词相交的结果:
var result = MyStringList.Select(s => s.Split())
.Aggregate(
MyStringList[0].Split().AsEnumerable(), // init accum with words from first string
(a, words) => a.Intersect(words), // intersect with next set of words
a => a);
输出:
[
"Bammler",
"GOV"
]
您可以从所有字符串中选择单词相交的结果:
var result = MyStringList.Select(s => s.Split())
.Aggregate(
MyStringList[0].Split().AsEnumerable(), // init accum with words from first string
(a, words) => a.Intersect(words), // intersect with next set of words
a => a);
输出:
[
"Bammler",
"GOV"
]
我会选择@Sergey answer,但我想补充一点,您也可以使用散列来获取交叉点:
var list = new List < string >{ "Bammler Tokyo SA GOV",
"Zurich Bammler GOV",
"London Bammler 12 GOV",
"New Bammler York GOV"};
var hash = new HashSet<string> ( list.First().Split(' ') );
for (int i = 1; i < list.Count; i++)
hash.IntersectWith(list[i].Split(' '));
我会选择@Sergey answer,但我想补充一点,您也可以使用散列来获取交叉点:
var list = new List < string >{ "Bammler Tokyo SA GOV",
"Zurich Bammler GOV",
"London Bammler 12 GOV",
"New Bammler York GOV"};
var hash = new HashSet<string> ( list.First().Split(' ') );
for (int i = 1; i < list.Count; i++)
hash.IntersectWith(list[i].Split(' '));
你试过什么?你不能指望我们为你做所有的工作…StackOverflow的工作方式是这样的-你尝试自己解决任务,如果你有一些问题或错误或意外的结果,那么你给出问题描述,你当前的代码,并请别人帮助你。你尝试了什么?你不能指望我们为你做所有的工作…StackOverflow的工作方式是这样的-你尝试自己解决任务,如果你有一些问题或意外的结果,那么你给出问题描述,你的当前代码,并请别人帮助你。非常感谢Sergey!非常感谢,谢尔盖!