C# Nhibernate：映射条件多对多关系？

我有以下对象模型：

public class Organizer
{
    private int id;

    public virtual int Id
    {
        get { return id; }
        set { id = value; }
    }

    private string fullName = "";

    public virtual string FullName
    {
        get { return fullName; }
        set { fullName = value; }
    }

    private List<Email> emails = new List<Email>();

    public virtual List<Email> Emails
    {
        get { return emails; }
        set { emails = value; }
    }
}


public enum EmailType
{
    Primary, Secondary
}

public class Email
{
    private int iD;

    public virtual int ID
    {
        get { return iD; }
        set { iD = value; }
    }
    private string emailAddress = "";

    public virtual string EmailAddress
    {
        get { return emailAddress; }
        set { emailAddress = value; }
    }
    private EmailType emailType = EmailType.Primary;

    public virtual EmailType EmailType
    {
        get { return emailType; }
        set { emailType = value; }
    }

    private List<Organizer> organizers;

    public virtual List<Organizer> Organizers
    {
        get { return organizers; }
        set { organizers = value; }
    }
}

现在，我在弄清楚如何用nhibernate（不是流利的nhibernate）来映射这一点上遇到了严重的问题。基本上，我希望对其进行映射，以便在执行“session.Save（anOrganizer）”时，数据有时写入两个表，有时写入三个表。例如，假设我们有OrganizerA，他有三封电子邮件：email_1、email_2和email_3。email_1具有EmailType.Primary，而其他两个具有EmailType.Secondary。因此，当我们保存OrganizerA时，会发生以下情况：

OrganizerA的详细信息将被写入表格组织者

email_1、email_2和email_3都会写入EmailAddresses表（如果它们还不存在的话）

在Organizer_PrimaryKeys表中创建了一个新行，其中email_1的id被写为PrimaryKeyID，OrganizerA的id被写为OrganizerID（不要担心PrimaryKeyTypeID，我稍后会解决这个问题） 那么我该如何映射这种关系呢？到目前为止，我有以下几点：

<?xml version="1.0" encoding="utf-8" ?>
<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2"
                   assembly="BLL"
                   namespace="BusinessLogic">

  <class name="Organizer" table="Organizers">
    <id name="Id">
      <column name="ID"/>
      <generator class="native" />
    </id>
    <property name="FullName">
      <column name="FullName"/>
    </property>
    <bag name="Emails" table="Organizers_PrimaryKeys" inverse="false" cascade="all" lazy="true" >
      <key column="Id"/>
      <many-to-many class="Email" />
    </bag>
  </class>
</hibernate-mapping>

<?xml version="1.0" encoding="utf-8" ?>
<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2"
                   assembly="BLL"
                   namespace="BusinessLogic">

  <class name="Email" table="EmailAddresses">
    <id name="ID">
      <column name="ID"/>
      <generator class="native" />
    </id>
    <property name="EmailAddress" unique="true" type="string" >
      <column name="EmailAddress"/>
    </property>

  </class>
</hibernate-mapping>

---

我不知道要在Email.hbm.xml中放入什么来完成这个“有条件的”多对多关系。

Email\u 1、Email\u 2和Email\u 3作为属性附加到Organizers表中

您需要将发送到两个不同对象的主电子邮件和次电子邮件分开，因为它们不是同一种实体。将Organizer class a一对一关系添加到PrimaryEmail，并保留当前多对多的Secondary Email列表

<?xml version="1.0" encoding="utf-8" ?>
<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2"
               assembly="BLL"
               namespace="BusinessLogic">

   <class name="Organizer" table="Organizers">
   <id name="Id">
      <column name="ID"/>
      <generator class="native" />
   </id>
   <property name="FullName">
      <column name="FullName"/>
   </property>
   <one-to-one name="PrimaryEmail" class="PrimaryEmail" />
   <bag name="Emails" table="EmailAddresses" inverse="false" cascade="all" lazy="true" >
     <key column="Id"/>
     <many-to-many class="SecondaryEmail" />
   </bag>
  </class>

  <class name="PrimaryEmail" table="Organizers_PrimaryKeys">
    <id name="ID">
      <column name="ID"/>
      <generator class="native" />
    </id>
    <property name="EmailAddress" unique="true" type="string" >
      <column name="EmailAddress"/>
    </property>
  </class>

  <class name="SecondaryEmail" table="EmailAddresses">
    <id name="ID">
      <column name="ID"/>
      <generator class="native" />
    </id>
    <property name="EmailAddress" unique="true" type="string" >
      <column name="EmailAddress"/>
    </property>
  </class>

---

真的吗？这就是答案？我认为这是对标准化数据库模式的挑战。杜思君：这是一个黑客攻击，不是答案。谢谢你的回复。你肯定让我走对了路。有时我真的很难以一种更友好的方式对我的域模型进行不同的思考。最后，考虑到primaryEmail与organizer是一对一的关系，我只是将它作为一列添加到db中的Organizers表中，并相应地更改了organizer.hbm.xml。我准确地复制了你的第二封电子邮件建议。现在它工作得很好。非常感谢。

<?xml version="1.0" encoding="utf-8" ?>
<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2"
               assembly="BLL"
               namespace="BusinessLogic">

   <class name="Organizer" table="Organizers">
   <id name="Id">
      <column name="ID"/>
      <generator class="native" />
   </id>
   <property name="FullName">
      <column name="FullName"/>
   </property>
   <one-to-one name="PrimaryEmail" class="PrimaryEmail" />
   <bag name="Emails" table="EmailAddresses" inverse="false" cascade="all" lazy="true" >
     <key column="Id"/>
     <many-to-many class="SecondaryEmail" />
   </bag>
  </class>

  <class name="PrimaryEmail" table="Organizers_PrimaryKeys">
    <id name="ID">
      <column name="ID"/>
      <generator class="native" />
    </id>
    <property name="EmailAddress" unique="true" type="string" >
      <column name="EmailAddress"/>
    </property>
  </class>

  <class name="SecondaryEmail" table="EmailAddresses">
    <id name="ID">
      <column name="ID"/>
      <generator class="native" />
    </id>
    <property name="EmailAddress" unique="true" type="string" >
      <column name="EmailAddress"/>
    </property>
  </class>