C# AutoMapper-如何在自定义类型转换器内使用自定义值解析器

如何在自定义类型转换器中使用自定义值解析程序？ 目前，这在我看来很难实现。你知道我如何使用这门课吗

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人员转换器

class PersonConverter : ITypeConverter<PersonData, Person>
{
    public Person Convert(ResolutionContext context)
    {
        var personData = context.SourceValue as PersonData;
        if (personData == null)
        {
            return null;
        }

        var person = new Person
        {
            Name = personData.Name
        };
        //person.Dic = // use here my DictionaryResolver

        return person;
    }
}

class DictionaryResolver : ValueResolver<int, Dictionary>
{
    protected override Dictionary ResolveCore(int source)
    {
        // do something
        return new Dictionary
        {
            Id = source,
            Name = "Name"
        };
    }
}

值解析器

class PersonConverter : ITypeConverter<PersonData, Person>
{
    public Person Convert(ResolutionContext context)
    {
        var personData = context.SourceValue as PersonData;
        if (personData == null)
        {
            return null;
        }

        var person = new Person
        {
            Name = personData.Name
        };
        //person.Dic = // use here my DictionaryResolver

        return person;
    }
}

class DictionaryResolver : ValueResolver<int, Dictionary>
{
    protected override Dictionary ResolveCore(int source)
    {
        // do something
        return new Dictionary
        {
            Id = source,
            Name = "Name"
        };
    }
}

类字典Resolver:ValueResolver
{
受保护的重写字典ResolveCore（int源）
{
//做点什么
返回新词典
{
Id=源，
Name=“Name”
};
}
}

自定义值解析程序设计用于在AutoMapper映射对象时覆盖特定成员的映射：

Mapper.CreateMap<PersonData, Person>()
                .ForMember(dest => dest.Dic, opt => opt.ResolveUsing<DictionaryResolver>());

然后在类型转换期间调用它来解析该属性：

var person = new Person
    {
        Name = personData.Name
    };

DictionaryResolver resolver = new DictionaryResolver();
person.Dic = resolver.Resolve(personData.IntValue); // whatever value you use

---

谢谢，这是一个很好的回答

var person = new Person
    {
        Name = personData.Name
    };

DictionaryResolver resolver = new DictionaryResolver();
person.Dic = resolver.Resolve(personData.IntValue); // whatever value you use