XmlSerializer如何排除空值但保留标记?c#
我的班级XmlSerializer如何排除空值但保留标记?c#,c#,asp.net,xml-serialization,nullable,xmlserializer,C#,Asp.net,Xml Serialization,Nullable,Xmlserializer,我的班级 public MyClass { [DataMemberAttribute(EmitDefaultValue = true)] public decimal? a { get; set; } [DataMemberAttribute(EmitDefaultValue = true)] public DateTime? b { get; set; } [DataMemberAttribute(EmitD
public MyClass
{
[DataMemberAttribute(EmitDefaultValue = true)]
public decimal? a { get; set; }
[DataMemberAttribute(EmitDefaultValue = true)]
public DateTime? b { get; set; }
[DataMemberAttribute(EmitDefaultValue = true)]
public int? c { get; set; }
[DataMemberAttribute(EmitDefaultValue = true)]
public bool? d { get; set; }
}
Decimal、DateTime和int可为空。因此,我:
<MyClass ...>
<a>3</a>
<b i:nil="true"/>
<c i:nil="true"/>
<d i:nil="true"/>
</MyClass>
3.
当a,b,c为空时,我想得到:
<MyClass ...>
<a>3</a>
<b/>
<c/>
<d/>
</MyClass>
3.
您只需为所需的每个元素创建如下属性:
public MyClass
{
[System.Xml.Serialization.XmlElement("b",IsNullable = false)]
public object b
{
get
{
return b;
}
set
{
if (value == null)
{
b = null;
}
else if (value is DateTime || value is DateTime?)
{
b = (DateTime)value;
}
else
{
b = DateTime.Parse(value.ToString());
}
}
}
//public object b ....
}
我终于做到了:
XmlSerializer.SerializeToWriter(data, strw);
XDocument xdoc = XDocument.Load("myxmlfile.xml");
foreach (var attribute in xdoc.Descendants())
{
if (attribute.FirstAttribute != null && attribute.FirstAttribute.ToString().Contains("i:nil"))
attribute.FirstAttribute.Remove();
}
xdoc.Save("myxmlfile.xml");
在我的班上我有
[DataMemberAttribute(EmitDefaultValue = true)]
所以当它为null时,它会生成'i:nil=“true”',然后我只需要删除它