readf未在循环try-catch中正确分配

如果在下面的程序中键入“a”作为输入，而不是整数，则输出将进入循环，而不会停止以获取更多输入。为什么?

uint inputInt = 1;
while (inputInt > 0) {
  write("enter something: ");
  try {
    readf(" %s", inputInt);
    writefln("inputInt is: %s", inputInt);
  }
  catch (Exception ex) {
    writeln("does not compute, try again.");
    inputInt = 1;
  }
}

我希望

inputInt

在

catch

块中被分配“1”，然后

try

块将再次执行。但是，输出显示程序不会再次停止收集

输入

：

enter something: does not compute, try again.
enter something: does not compute, try again.
enter something: does not compute, try again.
enter something: does not compute, try again.
enter something: does not compute, try again.
etc...

---

因为当

readf

失败时，它不会从缓冲区中删除输入。因此，下一次循环再次失败

试试这个：

import std.stdio;
void main()
{
    uint inputInt = 1;
    while (inputInt > 0) {
        write("enter something: ");
        try {
            readf(" %s", inputInt);
            writefln("inputInt is: %s", inputInt);
        }
        catch (Exception ex) {
            readln(); // Discard current input buffer
            writeln("does not compute, try again.");
            inputInt = 1;
        }
    }
}