Database 使用Oracle 12C查找具有匹配项的断开序列

我想检测每个数字的CDR_ID序列中的间隔，因为我正在使用match_recognize分析函数

代码：

这是我得到的结果：

NUMBER          CDR_ID      STATUS_SEQUENCE                         
003301011849    536         1
003301011849    537         2
003301011849    538         3
003301011849    539         4
003301011849    540         5
003301011849    541         6
003301011849    542         7
003301011849    544         8           <-- !!! 
003301011849    545         9
003301011849    546         10
003301011849    547         11
003301011849    548         12

编号CDR\u ID状态\u序列 003301011849 536 1 003301011849 537 2 003301011849 538 3 003301011849 539 4 003301011849 540 5 003301011849 541 6 003301011849 542 7

---

003301011849 544 8将一些分析相互叠加

with detect_first_in_seq$ as (
    select X.*,
        case when lnnvl(lag(X.cdr_id) over (partition by num order by cdr_id) = X.cdr_id-1) then X.cdr_id end as is_first_cdr_id_in_seq
    from tmp_cdr_gaps X
),
copy_first_in_seq$ as (
    select X.*,
        last_value(is_first_cdr_id_in_seq ignore nulls) over (partition by num order by cdr_id) as first_cdr_id_in_seq
    from detect_first_in_seq$ X
)
select
    X.*,
    row_number() over (partition by num, first_cdr_id_in_seq order by cdr_id) as status_sequence
from copy_first_in_seq$ X
;

通过您的一个稍微修改的查询和一个额外的分析

select num, cdr_id,
    row_number() over (partition by num, sequence_group order by cdr_id) as status_sequence
from tmp_cdr_gaps
    match_recognize (
        partition by num
        order     by cdr_id
        measures  match_number() sequence_group
        all rows per match
        after match skip past last row
        pattern   (section_start in_seq_value*)
        define    in_seq_value as (cdr_id = prev(cdr_id)+1)
    );

最后，使用

match\u recognize

only

select *
from tmp_cdr_gaps
    match_recognize (
        partition by num
        order by cdr_id
        measures count(1) as status_sequence
        all rows per match
        after match skip past last row
        pattern (sequence_group in_sequence*)
        define in_sequence as (cdr_id = prev(cdr_id)+1)
    );

这似乎是可行的，因为我发现，

match\u recognize（）

中的聚合函数具有运行聚合的默认操作方式

也感谢您让我更接近于掌握这一对SQL的精彩补充。：-）

至于你，有人能帮我了解一下匹配的语法有什么问题吗

有很多事情是错误的：

定义为

cdr\u id=prev（cdr\u id）

的

in\u seq\u值没有意义。根据这个定义，您是说您想要识别相同
cdr\u id
值的序列，而实际上您想要识别增加1的
cdr\u id
值的序列

您的

match_number（）status_sequence

按顺序为每个找到的模式编号。对于

cdr\u id=prev（cdr\u id）

。对于

cdr\u id=prev（cdr\u id）+1

，对于

cdr\u id

从

536

到

542

的行以及

cdr\u id

从

544

到

548

的行，这将是

1

select *
from tmp_cdr_gaps
    match_recognize (
        partition by num
        order by cdr_id
        measures count(1) as status_sequence
        all rows per match
        after match skip past last row
        pattern (sequence_group in_sequence*)
        define in_sequence as (cdr_id = prev(cdr_id)+1)
    );