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Debugging Valgrind在Fortran代码中显示未初始化的变量_Debugging_Fortran_Valgrind - Fatal编程技术网

Debugging Valgrind在Fortran代码中显示未初始化的变量

Debugging Valgrind在Fortran代码中显示未初始化的变量,debugging,fortran,valgrind,Debugging,Fortran,Valgrind,我正在Fortran应用程序上执行valgrind(使用memcheck工具)。 valgrind显示以下错误: ==17072== at 0x806C4A2: prove_ (t10_isb.f90:1948) ==17072== by 0x804E9F3: anal1_ (t10_isb.f90:2721) ==17072== by 0x808EECC: MAIN__ (t10_isb.f90:6) ==17072== by 0x808EF14: main (t10_

我正在Fortran应用程序上执行valgrind(使用memcheck工具)。 valgrind显示以下错误:

==17072==    at 0x806C4A2: prove_ (t10_isb.f90:1948)
==17072==    by 0x804E9F3: anal1_ (t10_isb.f90:2721)
==17072==    by 0x808EECC: MAIN__ (t10_isb.f90:6)
==17072==    by 0x808EF14: main (t10_isb.f90:8)
==17072==  Uninitialised value was created by a stack allocation
==17072==    at 0x805ECDC: relplm_ (t10_isb.f90:3402)
==17072== 
==17072== 
==17072== ---- Attach to debugger ? --- [Return/N/n/Y/y/C/c] ---- y
查看源代码,我没有发现任何可疑之处:

这里,在1948行,使用了未初始化的变量,所以我猜它是ER或EZ:

1943             if(NIT.eq.0) then
1944                  ER=ER/ekran
1945                  EZ=EZ/ekran
1946             end if
1947
1948                EM=DSQRT(ER*ER+EZ*EZ)
1949                ENO=-ER*PK(IEM*9-7)+EZ*PK(IEM*9-5)
1950
1951                IF(PK(IEM*9-8).GE.0.5D0) THEN
1952                   ESS=(ER*(PK(IEM*9-4)-F1)+EZ*(PK(IEM*9-6)-F2))
然而,在调用堆栈上,我们可以看到这些变量直接初始化为调用PROVE子例程

2716
2717          CALL VECMUL(SQ,JJK,CUR,NTP)
2718
2719          ER=0.D0
2720          EZ=0.D0
2721          CALL PROVE(E0,ES1,EN2,TE,TEPR,TEMI,TEMA,RB,ZB,QS,QP,R1P,Z1P,RONAT,ROHQ,RNQ,ZNQ,QNQ,NQ,IM1,IM2,IM3,IM4,IM5,IQQ,NTP,NIT,US,NFR,NTPE,NEM,NR,KEYP,MSYS,ekran,UK,RK,ZK,ER,EZ,F1,F2)
2722
2723          NPPP=NPAOLD+1
2724          DO I=NPPP,NPA
2725            N=I-NPAOLD

在阅读了valgrind和memcheck之后,我发现我应该更加注意这一点:

==17072==  Uninitialised value was created by a stack allocation
==17072==    at 0x805ECDC: relplm_ (t10_isb.f90:3402)
我希望Valgrind能告诉我从未初始化的变量中第一次读取的位置,但是它只在“unitialized”传播到syscall或条件跳转中使用的变量时显示

我的问题是ER变量是以以下方式初始化的(不是真正的代码,结构类似,但是伪C):


其中一个变量不声明为静态(或显式)很难做到,因为在FORTRAN77中,您可以通过变量名称开头的字母隐式声明变量类型。

阅读valgrind和memcheck之后,事实证明,我应该更加注意这一点:未初始化的值是由0x805ECDC:relplm_(t10_isb.f90:3402)处的堆栈分配创建的。变量ER和EZ在这里似乎是从一些未初始化的变量计算出来的(我必须进一步挖掘以找出哪些变量)。您是否使用flag
-Wuninitialized
进行编译?是的,很少有问题显示出来,但不是这一个。事实证明,子程序RELPLM使用了一些它期望是静态的变量,但它们不是。
int relplm() {
   static int a11, a12, a13, a21, a31, a32, a33;

   if (value of top-left cell calculated) a11...
   if (value of top-center cell calculated) a12...
   if (value of top-right cell calculated) a13...
   if (value of left cell calculated) a21...
   if (value of right cell calculated) a23...
   if (value of bottom-left cell calculated) a31...
   if (value of bottom-right cell calculated) a32...
   if (value of bottom-right cell calculated) a33...

   if (any of the values changed) er=f(a11,a12,a13,a21,a23,a31,a32,a33)
}