带分页的django排序表

我想对我的表列进行双向排序（升序和降序，按下按钮后切换）。我遇到的问题是，当我切换页面时，我的表格会出现故障

views.py

def company_index(request):
    order_by = request.GET.get('order_by')
    companies = Company.objects.all().order_by(Lower(order_by))

    paginator = Paginator(companies, 10)
    page = request.GET.get('page')
    try:
        all_companies = paginator.page(page)
    except PageNotAnInteger:
        all_companies = paginator.page(1)
    except EmptyPage:
        all_companies = paginator.page(paginator.num_pages)

    return render(request, 'companies/company_index.html',
                  {'all_companies': all_companies})

以下是我在模板中显示数据的方式（为了更好地显示帖子，我缩短了类名）：

公司名称
公司地址
税号
公司ID
KRS数

我的分页代码：

<ul class="pagination">
    {% if all_companies.has_previous %}
    <li><a href="?page={{ all_companies.previous_page_number }}&?order_by={{order_by}}">previous</a></li>
    {% endif %}
    <li class="disabled"><a>Page {{ all_companies.number }} of {{ all_companies.paginator.num_pages }}</a></li>
    {% if all_companies.has_next %}
    <li><a href="?page={{ all_companies.next_page_number }}&?order_by={{order_by}}">next</a></li>
    {% endif %}
</ul>

{%如果所有的公司都有以前的%}

{%endif%}

{%endif%}

当我切换到其他页面时{{order_by}}不会传递任何消息。另外，按下按钮后，如何使其按降序或升序排序

---

我想在没有外部应用程序或库的情况下进行此操作，以便更好地了解django。

您忘记在上下文中添加

order\u by

：

return render(request, 'companies/company_index.html',
              {'all_companies': all_companies, 'order_by': order_by})

模板中的升序/降序：

<a href="?order_by=company_name&direction=asc">company name ascending</a>
<a href="?order_by=company_name&direction=desc">company name descending</a>
...
<a href="?page={{ all_companies.previous_page_number }}&order_by={{ order_by }}&direction={{ direction }}">previous</a>
...
<a href="?page={{ all_companies.next_page_number }}&order_by={{ order_by }}&direction={{ direction }}">next</a>

<a href="?order_by=company_name&direction=asc">company name ascending</a>
<a href="?order_by=company_name&direction=desc">company name descending</a>
...
<a href="?page={{ all_companies.previous_page_number }}&order_by={{ order_by }}&direction={{ direction }}">previous</a>
...
<a href="?page={{ all_companies.next_page_number }}&order_by={{ order_by }}&direction={{ direction }}">next</a>

def company_index(request):
    order_by = request.GET.get('order_by')
    direction = request.GET.get('direction')
    ordering = Lower(order_by)
    if direction == 'desc':
        ordering = '-{}'.format(ordering)
    companies = Company.objects.all().order_by(ordering)

    paginator = Paginator(companies, 10)
    page = request.GET.get('page')
    try:
        all_companies = paginator.page(page)
    except PageNotAnInteger:
        all_companies = paginator.page(1)
    except EmptyPage:
        all_companies = paginator.page(paginator.num_pages)

    return render(request, 'companies/company_index.html',
                  {'all_companies': all_companies, 
                   'order_by': order_by, 'direction': direction})