Exception Symfony2-操纵来自内核异常侦听器的请求/响应
我正在为一个网站构建一个管理面板,我想更改当404异常发生时调用的视图,但仅适用于管理应用程序<代码>(路径:/admin/*) 我已经对网站的Exception Symfony2-操纵来自内核异常侦听器的请求/响应,exception,symfony,event-listener,Exception,Symfony,Event Listener,我正在为一个网站构建一个管理面板,我想更改当404异常发生时调用的视图,但仅适用于管理应用程序(路径:/admin/*) 我已经对网站的error404.html.twig视图(位于app/Resources/TwigBundle/views/Exception/)做了过度修改 我想到了kernel.exception事件监听器,但现在我遇到了两件事: 仅当路由以前缀开始时加载另一个错误视图:/admin/ $route = $event->getRequest->get('_ro
error404.html.twig
视图(位于app/Resources/TwigBundle/views/Exception/
)做了过度修改
我想到了kernel.exception事件监听器,但现在我遇到了两件事:
- 仅当路由以前缀开始时加载另一个错误视图:
/admin/
$route = $event->getRequest->get('_route')->render() //returns NULL
- 调用
函数$event->container->get('templating')->render()
- 正在检索异常代码:
$exception = $event->getException(); $code = $exception->getCode();
- 创建新的响应:
$response = new Response(); $event->setResponse($response);
namespace Cmt\AdminBundle\EventListener;
use Symfony\Component\DependencyInjection\ContainerInterface;
use Symfony\Bundle\TwigBundle\TwigEngine;
class AdminActionListener
{
/**
* @var ContainerInterface
*/
protected $container;
/**
* @var TwigEngine
*/
protected $templating;
/**
* @param ContainerInterface $container
*/
public function __construct(ContainerInterface $container, TwigEngine $templating){
// assign value(s)
$this->container = $container;
$this->templating = $templating;
}
/**
*
* @param GetResponseForExceptionEvent $event
*/
public function onKernelException(GetResponseForExceptionEvent $event)
{
// get exception
$exception = $event->getException();
// get path
$path = $event->getRequest()->getPathInfo();
/*
* Redirect response to new 404 error view only
* on path prefix /admin/
*/
}
}
以及服务。yml:
services:
cmt_admin.exception.action_listener:
class: Cmt\AdminBundle\EventListener\AdminActionListener
arguments: [@service_container] [@templating]
tags:
- { name: kernel.event_listener, event: kernel.exception, method: onKernelException }
你可以试试这个:
public function __construct(TwigEngine $templating)
{
$this->templating = $templating;
}
public function onKernelException(GetResponseForExceptionEvent $event)
{
static $handling;
$exception = $event->getException();
if (true === $handling) {
return;
}
$handling = true;
$code = $exception->getCode();
if (0 !== strpos($event->getRequest()->getPathInfo(), '/admin') && 404 === $code) {
$message = $this->templating->render('AcmeBundle:Default:error404new.html.twig', array());
$response = new Response($message, $code);
$event->setResponse($response);
}
$handling = false;
}
$templating变量可以在services.xml中传递:
<service id="acme.exception.listener" class="%acme.exception.listener.class%">
<tag name="kernel.event_listener" event="kernel.exception" method="onKernelException" />
<argument type="service" id="templating" />
</service>
出于某种原因,这起作用了:
// get exception
$exception = $event->getException();
// get path
$path = $event->getRequest()->getPathInfo();
if ($exception->getStatusCode() == 404 && strpos($path, '/admin') === 0){
$templating = $this->container->get('templating');
$response = new Response($templating->render('CmtAdminBundle:Exception:error404.html.twig', array(
'exception' => $exception
)));
$event->setResponse($response);
}
这基本上就是我之前用不同的语法做的
@不管怎样,谢谢你的帮助 嗨,谢谢你的回答。我试图传递$templating,但得到以下错误:
ErrorException:Catchable致命错误:传递给Cmt\AdminBundle\EventListener\AdminActionListener的参数1::\uu construct()必须是Symfony\Bundle\TwigBundle\TwigEngine的实例
您是否已添加到如上所示的服务中?嗯。此服务(“模板化”)在vendor/symfony/src/symfony/Bundle/FrameworkBundle/DependencyInjection/FrameworkExtension.php中定义。因此,您可能安装了过时的Symfony2,或者以某种方式禁用了Twig。。您使用的Symfony的确切版本是什么?您可以检查我提到的文件吗?您还可以尝试删除显式类型检查,即:“公共函数构造($templating)”版本Symfony Standard 2.0.1。删除类型检查会引发此错误:缺少Cmt\AdminBundle\EventListener\AdminActionListener::\uu construct()我也尝试使用FrameworkExtension,但它不起作用。另外,命令app/console container:debug
返回以下内容:templating container->Symfony\Bundle\TwigBundle\TwigEngine