Google bigquery 如何在Google BigQuery中执行三元操作?

Google bigquery 如何在Google BigQuery中执行三元操作?,google-bigquery,similarity,trigram,Google Bigquery,Similarity,Trigram,我确实使用PostgreSQL中的pg_trgm模块使用三叉图计算两个字符串之间的相似性。我特别使用: similarity(text, text) 它返回一个数字,指示两个参数在0和1之间的相似程度 如何在Google BigQuery上执行相似性功能或等效功能?请尝试以下内容。至少作为一个增强 SELECT text1, text2, similarity FROM JS( // input table ( SELECT * FROM (SELECT 'mikhail' AS

我确实使用PostgreSQL中的pg_trgm模块使用三叉图计算两个字符串之间的相似性。我特别使用:

similarity(text, text)
它返回一个数字,指示两个参数在0和1之间的相似程度


如何在Google BigQuery上执行相似性功能或等效功能?

请尝试以下内容。至少作为一个增强

SELECT text1, text2, similarity FROM 
JS(
// input table
(
  SELECT * FROM 
  (SELECT 'mikhail' AS text1, 'mikhail' AS text2),
  (SELECT 'mikhail' AS text1, 'mike' AS text2),
  (SELECT 'mikhail' AS text1, 'michael' AS text2),
  (SELECT 'mikhail' AS text1, 'javier' AS text2),
  (SELECT 'mikhail' AS text1, 'thomas' AS text2)
) ,
// input columns
text1, text2,
// output schema
"[{name: 'text1', type:'string'},
  {name: 'text2', type:'string'},
  {name: 'similarity', type:'float'}]
",
// function
"function(r, emit) {

  var _extend = function(dst) {
    var sources = Array.prototype.slice.call(arguments, 1);
    for (var i=0; i<sources.length; ++i) {
      var src = sources[i];
      for (var p in src) {
        if (src.hasOwnProperty(p)) dst[p] = src[p];
      }
    }
    return dst;
  };

  var Levenshtein = {
    /**
     * Calculate levenshtein distance of the two strings.
     *
     * @param str1 String the first string.
     * @param str2 String the second string.
     * @return Integer the levenshtein distance (0 and above).
     */
    get: function(str1, str2) {
      // base cases
      if (str1 === str2) return 0;
      if (str1.length === 0) return str2.length;
      if (str2.length === 0) return str1.length;

      // two rows
      var prevRow  = new Array(str2.length + 1),
          curCol, nextCol, i, j, tmp;

      // initialise previous row
      for (i=0; i<prevRow.length; ++i) {
        prevRow[i] = i;
      }

      // calculate current row distance from previous row
      for (i=0; i<str1.length; ++i) {
        nextCol = i + 1;

        for (j=0; j<str2.length; ++j) {
          curCol = nextCol;

          // substution
          nextCol = prevRow[j] + ( (str1.charAt(i) === str2.charAt(j)) ? 0 : 1 );
          // insertion
          tmp = curCol + 1;
          if (nextCol > tmp) {
            nextCol = tmp;
          }
          // deletion
          tmp = prevRow[j + 1] + 1;
          if (nextCol > tmp) {
            nextCol = tmp;
          }

          // copy current col value into previous (in preparation for next iteration)
          prevRow[j] = curCol;
        }

        // copy last col value into previous (in preparation for next iteration)
        prevRow[j] = nextCol;
      }

      return nextCol;
    }

  };

  var the_text1;

  try {
    the_text1 = decodeURI(r.text1).toLowerCase();
  } catch (ex) {
    the_text1 = r.text1.toLowerCase();
  }

  try {
    the_text2 = decodeURI(r.text2).toLowerCase();
  } catch (ex) {
    the_text2 = r.text2.toLowerCase();
  }

  emit({text1: the_text1, text2: the_text2,
        similarity: 1 - Levenshtein.get(the_text1, the_text2) / the_text1.length});

  }"
)
ORDER BY similarity DESC
这是基于@thomaspark的光线修改

我喜欢这样:

CREATE TEMP FUNCTION trigram_similarity(a STRING, b STRING) AS (
  (
    WITH a_trigrams AS (
      SELECT
        DISTINCT tri_a
      FROM
        unnest(ML.NGRAMS(SPLIT(LOWER(a), ''), [3,3])) AS tri_a
    ),
    b_trigrams AS (
      SELECT
        DISTINCT tri_b
      FROM
        unnest(ML.NGRAMS(SPLIT(LOWER(b), ''), [3,3])) AS tri_b
    )
    SELECT
      COUNTIF(tri_b IS NOT NULL) / COUNT(*)
    FROM
      a_trigrams
      LEFT JOIN b_trigrams ON tri_a = tri_b
  )
);
以下是与以下内容的比较:


谢谢米哈伊尔,它真的很管用!我将在规模上测试它的性能。希望BigQuery团队在不久的将来能够整合这些功能。这对于大数据的匹配非常有用。
select trigram_similarity('saemus', 'seamus');
-- 0.25 vs. pg_trgm 0.272727

select trigram_similarity('shamus', 'seamus');
-- 0.5 vs. pg_trgm 0.4