使用SLRequest的iOS转发返回错误的URL错误

我正在实现一个转发功能，但是在我的帖子发布后，我一直收到一个错误的URL。 这是我的密码：

SLRequest *twitterRequest = [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodPOST URL:[NSURL URLWithString:@"https://api.twitter.com/1.1/statuses/retweet/%@.json"] parameters:[NSDictionary dictionaryWithObject:tweetId forKey:@"id"]];

[twitterRequest performRequestWithHandler:^(NSData *responseData, NSHTTPURLResponse *urlResponse, NSError *error) {
  dispatch_async(dispatch_get_main_queue(), ^{

    if ([urlResponse statusCode] == 429) {
        NSLog(@"Rate limit reached");
        return;
    }

    if (error) {
        NSLog(@"Error: %@", error.localizedDescription);
        return;
    }

  });
}];

有什么想法吗？我遗漏了什么吗？谢谢

取而代之的是

   SLRequest *twitterRequest = [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodPOST URL:[NSURL URLWithString:@"https://api.twitter.com/1.1/statuses/retweet/%@.json"] parameters [NSDictionary dictionaryWithObject:tweetId forKey:@"id"]];

 SLRequest *twitterRequest = [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodPOST URL:[NSURL URLWithString:@"https://api.twitter.com/1.1/statuses/retweet/%@.json"] parameters:[NSDictionary dictionaryWithObject:tweetId forKey:@"status"]];

   SLRequest *twitterRequest = [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodPOST URL:[NSURL URLWithString:@"https://api.twitter.com/1.1/statuses/retweet/%@.json"] parameters [NSDictionary dictionaryWithObject:tweetId forKey:@"id"]];

 SLRequest *twitterRequest = [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodPOST URL:[NSURL URLWithString:@"https://api.twitter.com/1.1/statuses/retweet/%@.json"] parameters:[NSDictionary dictionaryWithObject:tweetId forKey:@"status"]];

试试这个

   SLRequest *twitterRequest = [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodPOST URL:[NSURL URLWithString:@"https://api.twitter.com/1.1/statuses/retweet/%@.json"] parameters [NSDictionary dictionaryWithObject:tweetId forKey:@"id"]];

 SLRequest *twitterRequest = [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodPOST URL:[NSURL URLWithString:@"https://api.twitter.com/1.1/statuses/retweet/%@.json"] parameters:[NSDictionary dictionaryWithObject:tweetId forKey:@"status"]];

   SLRequest *twitterRequest = [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodPOST URL:[NSURL URLWithString:@"https://api.twitter.com/1.1/statuses/retweet/%@.json"] parameters [NSDictionary dictionaryWithObject:tweetId forKey:@"id"]];

 SLRequest *twitterRequest = [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodPOST URL:[NSURL URLWithString:@"https://api.twitter.com/1.1/statuses/retweet/%@.json"] parameters:[NSDictionary dictionaryWithObject:tweetId forKey:@"status"]];

一件事你不能一次又一次地重发同一条消息，它会被认为是垃圾邮件。

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同时也看到这一点，你可能会错过一些我不好的东西。我在创建请求“…%@.json”时忘记传递字符串

i、 e

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您应该在申请中附上一个帐户

// create a request
NSURL *url = [NSURL URLWithString:@"https://api.twitter.com/1.1/statuses/user_timeline.json"];

SLRequest *request = [SLRequest requestForServiceType:SLServiceTypeTwitter
                                        requestMethod:SLRequestMethodGET
                                                  URL:url
                                           parameters:@{@"screen_name":@"nst021"}];

// attach an account to the request
NSArray *twitterAccounts = [accountStore accountsWithAccountType:twitterAccountType];
[request setAccount:[twitterAccounts lastObject]];

// execute the request
[request performRequestWithHandler:^(NSData *responseData,
                                     NSHTTPURLResponse *urlResponse,
                                     NSError *error) {
    // caution, you're on an arbitrary queue here...
}

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我试过了，还从链接上查看了你的代码，每次都得到403。你在你的设备上设置了帐户吗？我设置了，但我刚刚意识到我做错了什么。事实上，我的代码是正确的，除了我忘了传递字符串：pMay be u达到了更新限制，看到了吗