Parse.com检查friendRequest复制iOS
我希望通过Parse.com和云代码或iOS代码避免重复。 这是我在数据库中的课程: 我希望当“from”用户ID已经发送到“to”用户ID时,不会发送第二个friendRequest 这是我的iOS代码:Parse.com检查friendRequest复制iOS,ios,objective-c,parse-platform,parse-cloud-code,friendrequest,Ios,Objective C,Parse Platform,Parse Cloud Code,Friendrequest,我希望通过Parse.com和云代码或iOS代码避免重复。 这是我在数据库中的课程: 我希望当“from”用户ID已经发送到“to”用户ID时,不会发送第二个friendRequest 这是我的iOS代码: PFUser *selectedUser = [self.allUsers objectAtIndex:indexPath.row]; //request them PFObject *friendRequest = [PFObject objectWithClassName:@"Frie
PFUser *selectedUser = [self.allUsers objectAtIndex:indexPath.row];
//request them
PFObject *friendRequest = [PFObject objectWithClassName:@"FriendRequest"];
friendRequest[@"from"] = self.currentUser;
friendRequest[@"fromUsername"] = [[PFUser currentUser] objectForKey:@"username"];
//selected user is the user at the cell that was selected
friendRequest[@"to"] = selectedUser;
// set the initial status to pending
friendRequest[@"status"] = @"pending";
[friendRequest saveInBackgroundWithBlock:^(BOOL succeeded, NSError *error) {
if (succeeded) {
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Sent !" message:@"Friend request sent" delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil, nil];
[alert show];
} else {
// error occurred
}
}];
您好,如果您已经发送了好友请求或从“CurrentUser”发送到“SelectedUser”,您可以执行以下操作以获取好友:
-(void)fetchfriendrequestAndSave{
PFUser *selectedUser = [self.allUsers objectAtIndex:indexPath.row];
//request them
PFObject *friendRequest = [PFObject objectWithClassName:@"FriendRequest"];
friendRequest[@"from"] = self.currentUser;
friendRequest[@"fromUsername"] = [[PFUser currentUser] objectForKey:@"username"];
//selected user is the user at the cell that was selected
friendRequest[@"to"] = selectedUser;
// set the initial status to pending
friendRequest[@"status"] = @"pending";
PFQuery*query = [PFQuery queryWithClassName:@"FriendRequest"];
[query whereKey:@"from" equalTo:self.currentuser];
[query whereKey:@"to" equalTo: selectedUser];
[query findObjectsInBackgroundWithBlock:^(NSArray*FriendRequestArray, NSError*error){
if(!error){
NSArray*temp = [NSArray arrayWithArray:object];
if(temp.count==0){
//Save & Send Request
[friendRequest saveInBackgroundWithBlock:^(BOOL succeeded, NSError *error) {
if (succeeded) {
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Sent !" message:@"Friend request sent" delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil, nil];
[alert show];
} else {
// error occurred
}
}];
}else{
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"FriendREquest ERROR" message:@"Friend Request is Already Submitted" delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil, nil];
[alert show];
}
}else{
}
}];
}
通过PFQuery:
您可以在Parse.com服务的同一行中搜索“CurrentUser”和“SelectedUser”的值!如果是,它将返回一个数组“temp”…如果不是,它也将返回一个数组…但是如果它是0,我们将对这个数组进行计数(因此它意味着它里面没有值,简而言之…没有朋友请求”
如果(NSArray*temp.count==0)保存请求
希望这对你有帮助!对我来说很有效