Ios ContainerView-离不可见视图有多近
我有一个故事板: 该代码:Ios ContainerView-离不可见视图有多近,ios,swift,swift3,swift4,Ios,Swift,Swift3,Swift4,我有一个故事板: 该代码: var actualVisibleView : String? = nil func showSubViewInContainerView(view: String){ let controller = storyboard!.instantiateViewController(withIdentifier: view) addChildViewController(controller) controller.vi
var actualVisibleView : String? = nil
func showSubViewInContainerView(view: String){
let controller = storyboard!.instantiateViewController(withIdentifier: view)
addChildViewController(controller)
controller.view.translatesAutoresizingMaskIntoConstraints = false
systemContainerView.addSubview(controller.view)
NSLayoutConstraint.activate([
controller.view.leadingAnchor.constraint(equalTo: systemContainerView.leadingAnchor),
controller.view.trailingAnchor.constraint(equalTo: systemContainerView.trailingAnchor),
controller.view.topAnchor.constraint(equalTo: systemContainerView.topAnchor),
controller.view.bottomAnchor.constraint(equalTo: systemContainerView.bottomAnchor)
])
controller.didMove(toParentViewController: self)
if self.actualVisibleView != nil && self.actualVisibleView != view {
controller.dismiss(animated: false) {
print("UBIJAM: \(view)")
}
}
self.actualVisibleView = view
print("OTWIERAM: \(view)")
}
在左侧菜单中,我使用以下代码打开此containerview中的各种视图:
showSubViewInContainerView(view: "view1")
showSubViewInContainerView(view: "view2")
showSubViewInContainerView(view: "view3")
showSubViewInContainerView(view: "view4")
这个代码工作起来很轻松。唯一的问题是,当我在容器视图中打开一个新视图时,我想关闭以前可见的视图。
containerview中只有一个活动视图可见
目前有一些观点相互重叠
有人知道如何修复它吗?在容器中添加新视图之前,请删除其他视图
systemContainerView.subviews.forEach { $0.removeFromSuperview() }
systemContainerView.addSubview(controller.view)
在容器中添加新视图之前,请删除其他视图
systemContainerView.subviews.forEach { $0.removeFromSuperview() }
systemContainerView.addSubview(controller.view)