Ios 如何使用UnixTime标记对数组进行排序

我想按时间对数组排序。但问题是，时间以UNIX时间戳的形式存在于另一个数组（数组的子数组）中

这是格式。请任何人帮我整理一下

    (
    group,
    "The Comic Corner",
    ""
),
    (
    group,
    "Home Alone",
    ""
),
    (
    group,
    "Romantic Movies",
    ""
),
    (
    group,
    "Thriller Movies",
    ""
),
    (
    group,
    Badminton,
    ""
),
    (
    group,
    "Celebrity Gossip",
    ""
),
    (
    group,
    "Dark Night",
    ""
),
    (
    group,
    "Graphics Designer",
    ""
),
    (
    group,
    "I Just Wanna....",
    ""
),
    (
    group,
    Religion,
    ""
),
    (
    group,
    "English Movies",
    ""
),
    (
    group,
    "Music World",
    ""
),
    (
    group,
    "Actions Movies",
    ""
),
    (
    group,
    "Bed & Breakfast",
    ""
),
    (
    group,
    "Strategic Games",
    ""
),
    (
    group,
    "Beer Lovers",
    ""
),
    (
    group,
    Hackers,
    ""
),
    (
    group,
    "Darkroom-Darkroom",
    ""
),
    (
    group,
    "Arcade Games",
    ""
),
    (
    group,
    "Hindi Movies",
    ""
),
    (
    mood,
    Anxious,
    1386749684146
),
    (
    "profilepic_time",
    1386545975408
),
    (
    "status_msg",
    " *z32_ hell0",
    1386635654457
),
    (
    Broadcast,
    3,
    11,
    1372945566365
),
    (
    Broadcast,
    3,
    11,
    3
),
    (
    Broadcast,
    3,
    11,
    3
),
    (
    Broadcast,
    3,
    11,
    1372858799160
),
    (
    Broadcast,
    6,
    11,
    1372920363550
),
    (
    Broadcast,
    6,
    30,
    1373012360303
),
    (
    Broadcast,
    6,
    30,
    1373015204935
),
    (
    Broadcast,
    6,
    30,
    1373018547181
),
    (
    Broadcast,
    6,
    30,
    1373018768064
),
    (
    Broadcast,
    7,
    37,
    1373025360112
),
    (
    Broadcast,
    3,
    37,
    1373031270639
),
    (
    Broadcast,
    3,
    42,
    1373868972980
),
    (
    Broadcast,
    3,
    29,
    1372936645430
),
    (
    Broadcast,
    3,
    29,
    1372935983470
),
    (
    Broadcast,
    3,
    101,
    1374150527293
),
    (
    bulletin,
    "dbxjsbxdijxjdjxichdjdixhdbdjx hdjdbdh",
    1382331040766
),
    (
    bulletin,
    "aaabbb ccc dddd eee ffff",
    1382510132316
),
    (
    bulletin,
    "dvxishhxxbbosihdjxibididhxososjshsisos dijfjeosksn osjdjkd",
    1382510521856
),
    (
    bulletin,
    tsotdo,
    1382707279159
),
    (
    bulletin,
    84saurzuzri,
    1382707293764
),
    (
    bulletin,
    aiaktsktzyodld,
    1382707305875
),
    (
    bulletin,
    uarsistoso,
    1382707326326
),
    (
    bulletin,
    2e58e8etisististi,
    1382707335278
),
    (
    bulletin,
    ztkzktzgtkktotk,
    1382707484453
),
    (
    bulletin,
    ztkzktzgtkktotk9e85a4a47a48a37ariz,
    1382707491619
),
    (
    bulletin,
    "dbxidj didcxj",
    1384173984019
),
    (
    bulletin,
    "testing testing testing testing",
    1384589761276
),
    (
    bulletin,
    "testing testing testing testing",
    1384589772960
),
    (
    bulletin,
    "testing testing testing testing",
    1384589788706
),
    (
    bulletin,
    "testing testing testing testing",
    1384589822861
),
    (
    bulletin,
    "testing testing testing testing",
    1384589871332
),
    (
    bulletin,
    "testing testing testing testing",
    1384589875364
),
    (
    bulletin,
    "testing testing testing testing",
    1384589910927
),
    (
    bulletin,
    hey,
    1384589984774
),
    (
    bulletin,
    "heya ",
    1384590016235
),
    (
    bulletin,
    ok,
    1384597237610
),
    (
    bulletin,
    "hey ",
    1384605812061
),
    (
    bulletin,
    fhjfs,
    1384757502287
),

有些数组有时间戳，有些数组没有时间戳

这对我来说很复杂。有人能帮我吗

---

谢谢

您需要指定一个自定义比较器块，如下所示（您需要根据数据结构调整索引）：

如果希望非时间戳记录显示在时间戳记录之前，可以将

sensorderedescending

更改为

sensorderedescending

---

此外，我建议您避免将数据存储在

NSArray

s的

NSArray

中，并为您的项目创建适当的（如果需要，可以定义自己的排序功能）。

查看NSArray的任何“sortedarray使用…”方法，以及“sortUsing…：NSMutableArray的方法。我通常发现，对于我的脆弱的大脑来说，使用“…UsingFunction”风格并为比较器定义一个C风格的函数是最简单的，但其他人喜欢花哨的块东西。它不是从nsmutable数组中给出的排序方法中进行排序。我想我们必须手动排序。但是我找不到工作的确切逻辑。它是排序的，但我不知道排序字符串所用的参数是什么。在我的下一个评论中（组，“名人八卦”，“签入位置”，“公告，“测试”，“登记处”，138458875364），（广播，3,29,1372936645430），（团体，“动作电影”，“登记处”，”），（广播，6,30,1373018768064），（组，“黑夜”，“登记处”，“登记处”），如何正确排序日期请帮助meI查看各种记录具有不同数量的元素。您是否承诺时间戳在哪里，以及如何知道记录中是否不存在时间戳？如果我理解正确，则最后一个对象是

““

或时间戳本身。我已经根据那个猜测编辑了我的答案。

NSArray *array = @[@[@"a", @456], @[@"b", @123], @[@"c", @""]];

NSArray *sorted = [array sortedArrayUsingComparator:^NSComparisonResult(NSArray *a, NSArray *b) {
  if ([a.lastObject isKindOfClass:[NSNumber class]] &&
      [b.lastObject isKindOfClass:[NSNumber class]]) {
    return [a.lastObject compare:b.lastObject];
  }
  return NSOrderedAscending;
}];

NSLog(@"%@", sorted);