Ios 以纯swift 3方式将swift对象（带有嵌套对象）转换为JSON数据

我正在尝试将swift对象转换为JSON，我已经看到了这些问题，但我无法将其应用到我的代码中

我有一个类型为

[String:DailyTimes]

的swift对象，我想用纯swift3方式将其转换回JSON数据，而不需要任何库

下面是我的自定义类：

class AvailabilityTimes:{

    struct Times{
        var startTime : String?
        var endTime   : String?


    }

    struct DailyTimes{
        let weekday : String
        var available : Bool
        var times = [Times]()
        mutating func update(times: [Times]){
            self.times = times
        }

    }
}

转换的JSON数据（来自Swift对象）如下所示：

[
     "Monday": [ "weekday" : "Monday",
                 "available" : true,
                 "times": [
                     ["startTime": "9:00 AM", "endTime": "1:30 PM" ],
                     ["startTime": "2:30 PM", "endTime": "6:00 PM" ],
                     ["startTime": "7:30 PM", "endTime": "9:00 PM" ]
                 ]
     ],
     "Tuesday": [ "weekday" : "Tuesday",
                 "available" : true,
                 "times": [
                     ["startTime": "9:00 AM", "endTime": "6:00 PM" ]
                 ]
                 ]
     ]

我将

[String:DailyTimes]

转换为JSON数据的尝试失败

步骤1：在两个结构中都添加了convertToDictionary函数

class AvailabilityTimes:{

    struct Times{
        var startTime : String?
        var endTime   : String?

        func convertToDictionary() -> Dictionary<String, Any> {
            return [
                "startTime" : self.startTime,
                "endTime"   : self.endTime
            ]
        }
    }

    struct DailyTimes{
        let weekday : String
        var available : Bool
        var times = [Times]()
        mutating func update(times: [Times]){
            self.times = times
        }

        func convertToDictionary() -> Dictionary<String, Any> {
            return [
                "weekday"   : self.weekday,
                "available" : self.available,
                "times"     : self.times
            ]
        }

    }
} 

此方法：

JSONSerialization.data(withJSONObject: dictionary, options: .prettyPrinted)

要求

字典

为“属性列表”。一个是：

        [
            "weekday"   : self.weekday,
            "available" : self.available,
            "times"     : self.times
        ]

不是属性列表

func convertToDictionary() -> Dictionary<String, Any> {
    return [
        "weekday"   : self.weekday,
        "available" : self.available,
        "times"     : self.times.map{$0.convertToDictionary())
    ]
}

为什么?？因为

self.times

的类型为

[times]

，而不是属性列表类型。您需要在此处调用

self.times.map{$0.convertToDictionary（））

，以便将

times

转换为属性列表

func convertToDictionary() -> Dictionary<String, Any> {
    return [
        "weekday"   : self.weekday,
        "available" : self.available,
        "times"     : self.times.map{$0.convertToDictionary())
    ]
}

func convertToDictionary（）->字典{
返回[
“工作日”：self.weekday，
“可用”：自可用，
“times”：self.times.map{$0.convertToDictionary（））
]
}

试试这个：

struct DailyTimes{
    let weekday : String
    var available : Bool
    var times = [Times]()
    mutating func update(times: [Times]){
        self.times = times
    }

    func convertTimesToDictionary() -> [Any] {
        var timeDict:[Any] = []
        self.times.forEach({ timeDict.append($0.convertToDictionary())})
        return timeDict
    }

    func convertToDictionary() -> Dictionary<String, Any> {
        return [
            "weekday"   : self.weekday,
            "available" : self.available,
            "times"     : self.convertTimesToDictionary()
        ]
    }
}

---

更改此行

let dictionary=value.convertToDictionary（）

func convertToJSONObject(timesObject: [String : DailyTimes]) -> [String:AnyObject] {
    var dailyTimesObject:[String:AnyObject] = [:]
    for (key, value) in timesObject {
        dailyTimesObject.updateValue(value.convertToDictionary() as AnyObject, forKey: key)
    }
    return dailyTimesObject
}

func convertTimesObjectToJSON(timesObject: [String : DailyTimes]){
    do{
        let theJSONData = try JSONSerialization.data(withJSONObject: convertToJSONObject(timesObject: timesObject), options: .prettyPrinted)
        print(String(data: theJSONData, encoding: String.Encoding.utf8)!)
    } catch let error{
        print("error: \(error)")
    }
}