Ios 筛选唯一值以在邮件收件箱中显示唯一用户名

Ios 筛选唯一值以在邮件收件箱中显示唯一用户名,ios,swift,firebase,google-cloud-firestore,Ios,Swift,Firebase,Google Cloud Firestore,我想过滤receiverID,这样我将只获得唯一的receiverID。下面是我的代码: func collectionView(_ collectionView: UICollectionView, cellForItemAt indexPath: IndexPath) -> UICollectionViewCell{ let cell = collectionView.dequeueReusableCell(withReuseIdentifier: cellIdentifier

我想过滤receiverID,这样我将只获得唯一的receiverID。下面是我的代码:

func collectionView(_ collectionView: UICollectionView, cellForItemAt indexPath: IndexPath) -> UICollectionViewCell{
    let cell = collectionView.dequeueReusableCell(withReuseIdentifier: cellIdentifier, for: indexPath) as! InboxCollectionViewCell
    cell.inboxMessage.text = chats[indexPath.row].receiverID
    return cell
}



    func loadPosts() {
    let senderIDNumber = Auth.auth().currentUser?.uid
    let chatsRef = db.collection("chats")
    chatsRef.whereField("senderID", isEqualTo: senderIDNumber!)
        .addSnapshotListener { querySnapshot, error in
            guard let documents = querySnapshot?.documents else {
                print("Error fetching documents: \(error!)")
                return
            }
            for document in documents {
                let messageText = document.data()["message"] as? String
                let senderIDNumber = document.data()["senderID"] as? String
                let receiverIDNumber = document.data()["receiverID"] as? String
                let timestamp = document.data()["timestamp"] as? String
                let conversationsCounter = document.data()["conversationsCounter"] as? Int
                let chat = Chat(messageTextString: messageText!, senderIDNumber: senderIDNumber!, receiverIDNumber: receiverIDNumber!, timeStampString: timestamp!, conversationsCounterInt: conversationsCounter!)
                self.chats.append(chat)
                print(self.chats)
                self.collectionView.reloadData()
            }
    }
}

有没有关于如何过滤以便我的inboxMessage显示唯一用户的想法?我正在使用Firebase/Firestore作为我的数据库。

听起来你好像在试图按收件人对结果进行分组。Firestore的查询API中没有这样的GROUPBY子句。您必须自己循环所有消息,并将它们分组到客户端

chatsRef.whereField("senderID", isEqualTo: senderIDNumber!)
    .order(by: "receiverID")
    .addSnapshotListener { querySnapshot, error in
        ...
        let lastReceiverID = "";
        for document in documents {
            ...
            let receiverIDNumber = document.data()["receiverID"] as? String

            if receiverIDNumber != lastReceiverId {
              // TODO: do something with receiverIDNumber
            }
            lastReceiverId = receiverIDNumber
        }
事实上,您的数据模型目前看起来像是在所有用户之间有一个单一的、很长的聊天消息列表,这感觉像是从用于聊天的关系数据模型的非常直接的转换

在NoSQL数据库中,您通常希望数据建模更接近应用程序实际需要的数据。例如,您似乎试图显示给定发件人的所有邮件。在这种情况下,考虑将这些消息存储在单独的集合中。例如,如果您已经有一个顶级
/users
集合,那么您可以将他们在
子集合中发送的消息发送到下面:
/users/$uid/sent

有关数据建模注意事项的更多信息,请参阅和Todd关于Cloud Firestore(和)的视频系列