Ios UIWebview[UIThreadSafeNode\u ResponderForeEdit]崩溃

Ios UIWebview[UIThreadSafeNode\u ResponderForeEdit]崩溃,ios,uiwebview,keyboard,landscape,Ios,Uiwebview,Keyboard,Landscape,所以我有一个基于webview的应用程序。我做了一些键盘修改(不是问题,为了排除故障,我把它们全部删除了) 在iPhone 6+模拟器上,当处于横向模式时,如果复制了某个内容,并且您使用键盘粘贴按钮(而不是上下文按钮),应用程序将崩溃。我在尝试使用键盘剪切按钮时也注意到了这一点 以下事故如下: -[UIThreadSafeNode _responderForEditing]: unrecognized selector sent to instance 0x7ff4364344c0

所以我有一个基于webview的应用程序。我做了一些键盘修改(不是问题,为了排除故障,我把它们全部删除了)

在iPhone 6+模拟器上,当处于横向模式时,如果复制了某个内容,并且您使用键盘粘贴按钮(而不是上下文按钮),应用程序将崩溃。我在尝试使用键盘剪切按钮时也注意到了这一点

以下事故如下:

    -[UIThreadSafeNode _responderForEditing]: unrecognized selector sent to instance 0x7ff4364344c0
    *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[UIThreadSafeNode _responderForEditing]: unrecognized selector sent to instance 0x7ff4364344c0'
*** First throw call stack:
(
    0   CoreFoundation                      0x000000010df98f45 __exceptionPreprocess + 165
    1   libobjc.A.dylib                     0x000000010da12deb objc_exception_throw + 48
    2   CoreFoundation                      0x000000010dfa156d -[NSObject(NSObject) doesNotRecognizeSelector:] + 205
    3   CoreFoundation                      0x000000010deeeeea ___forwarding___ + 970
    4   CoreFoundation                      0x000000010deeea98 _CF_forwarding_prep_0 + 120
    5   UIKit                               0x000000010c31eb4a -[UIKeyboardLayoutStar touchDownWithKey:atPoint:executionContext:] + 1445
    6   UIKit                               0x000000010c878ef0 -[UIKeyboardTaskExecutionContext returnExecutionToParentWithInfo:] + 278
    7   UIKit                               0x000000010c3169de -[UIKeyboardLayoutStar performHitTestForTouchInfo:touchStage:executionContextPassingUIKBTree:] + 1525
    8   UIKit                               0x000000010c31de57 -[UIKeyboardLayoutStar touchDown:executionContext:] + 533
    9   UIKit                               0x000000011df96fb5 -[UIKeyboardLayoutStarAccessibility touchDown:executionContext:] + 61
    10  UIKit                               0x000000010c8793ab -[UIKeyboardTaskQueue continueExecutionOnMainThread] + 332
    11  UIKit                               0x000000010c1347bd -[UIKeyboardLayout touchDown:] + 159
    12  UIKit                               0x000000010c1352ef -[UIKeyboardLayout touchesBegan:withEvent:] + 415
    13  UIKit                               0x000000010bee2cc2 -[UIWindow _sendTouchesForEvent:] + 308
    14  UIKit                               0x000000010bee3c06 -[UIWindow sendEvent:] + 865
    15  UIKit                               0x000000010be932fa -[UIApplication sendEvent:] + 263
    16  UIKit                               0x000000011df66a29 -[UIApplicationAccessibility sendEvent:] + 77
    17  UIKit                               0x000000010be6dabf _UIApplicationHandleEventQueue + 6844
    18  CoreFoundation                      0x000000010dec5011 __CFRUNLOOP_IS_CALLING_OUT_TO_A_SOURCE0_PERFORM_FUNCTION__ + 17
    19  CoreFoundation                      0x000000010debaf3c __CFRunLoopDoSources0 + 556
    20  CoreFoundation                      0x000000010deba3f3 __CFRunLoopRun + 867
    21  CoreFoundation                      0x000000010deb9e08 CFRunLoopRunSpecific + 488
    22  GraphicsServices                    0x000000010ead2ad2 GSEventRunModal + 161
    23  UIKit                               0x000000010be7330d UIApplicationMain + 171
很明显,因为我使用的是网络视图,所以没有实际的文本视图

我将如何解决这个问题?我不在乎通过AppStore审查,所以欢迎使用私有API或其他非苹果批准的方法


如蒙协助,将不胜感激。谢谢。

这是苹果的bug,因为这个选择器应该传递给
UIResponder
,但是
UIThreadSafeNode
NSObject
的子类。为了解决这个问题,您可以实现
NSObject
category:

@interface UIView (FirstResponder)

-(id)findFirstResponder;

@end

@implementation UIView (FirstResponder)

- (id)findFirstResponder
{
    if (self.isFirstResponder) {
        return self;
    }
    for (UIView *subView in self.subviews) {
        id responder = [subView findFirstResponder];
        if (responder) return responder;
    }
    return nil;
}

@end


@interface NSObject (KeyboardBUI)

-(_Nonnull id)_responderForEditing;

@end

@implementation NSObject (KeyboardBUI)

-(_Nonnull id)_responderForEditing
{
    return self;
}

-(void)cut:(nullable id)sender
{
    NSString *selection = [[self getWebView] stringByEvaluatingJavaScriptFromString:@"window.getSelection().toString()"];
    [[self getWebView] stringByEvaluatingJavaScriptFromString:@"document.execCommand('delete', false, null)"];
    [UIPasteboard generalPasteboard].string = selection;
}

-(void)paste:(nullable id)sender
{
    NSString *text = [UIPasteboard generalPasteboard].string;
    [[self getWebView] stringByEvaluatingJavaScriptFromString:[NSString stringWithFormat:@"document.execCommand('insertHTML', false, '%@')", text]];
}

-(void)copy:(nullable id)sender
{
    NSString *selection = [[self getWebView] stringByEvaluatingJavaScriptFromString:@"window.getSelection().toString()"];
    [UIPasteboard generalPasteboard].string = selection;
}

-(void)toggleItalics:(nullable id)sender
{
    [[self getWebView] stringByEvaluatingJavaScriptFromString:@"document.execCommand(\"Italic\")"];
}

-(void)toggleUnderline:(nullable id)sender
{
    [[self getWebView] stringByEvaluatingJavaScriptFromString:@"document.execCommand(\"Underline\")"];
}

-(void)toggleBoldface:(nullable id)sender
{
    [[self getWebView] stringByEvaluatingJavaScriptFromString:@"document.execCommand(\"Bold\")"];
}

-(UIWebView * __nullable)getWebView
{
    UIWebView *retVal = nil;
    id obj = [[[[[UIApplication sharedApplication] keyWindow] findFirstResponder] superview] superview];
    if ([obj  isKindOfClass:[UIWebView class]]) {
        retVal = obj;
    }
    return retVal;
}

@end
注:我不知道这是否能通过苹果Appstore审查

ui查看(第一响应者)
此类别


从中复制/粘贴/剪切

我应该更新这个问题,因为现在我已经切换到使用WKWebView。因此,这不再是一个问题。但我还是很感激你的回答。我将向上投票,希望如果这有助于具有相同情况的人,他们可以将其标记为已接受的答案。除非在
粘贴中构建
execCommand
字符串时,您应该“转义”复制的文本中的任何撇号。一种方法是:
NSString*text=[[UIPasteboard generalPasteboard].string StringByReplacingOfString:@“'”with string:@“'”