Ios Swift 3不安全指针

我正在从Swift 2迁移到Swift 3，我在某一点上被卡住了

Swift 2

let arr = UnsafePointer<UInt32>(UnsafePointer<UInt8>(buf).advanced(by: off))
let msk = arr[0].bigEndian & 0x7fffffff

但是在第二行上面写着

类型“UnsafeRawPointer”没有下标成员

---

我如何才能成功地将其转换为Swift 3？

我想您正在寻找这样的产品：

let ppp = UnsafePointer<UInt8>(buf).advanced(by: off)
let arr = unsafeBitCast(ppp, to: UnsafeMutablePointer<UInt32>.self)

let ppp=UnsafePointer（buf）.advanced（by:off）
设arr=unsafeBitCast（ppp，收件人：UnsafeMutablePointer.self）

以下是使用withMemoryRebound执行该操作的方法： 本例中的容量为1，因为您只查看结果数组的第一个元素

let arr = UnsafePointer<UInt8>(buf).advanced(by: off)
let msk = arr.withMemoryRebound(to: UInt32.self, capacity: 1) { p in
    return p[0].bigEndian & 0x7fffffff
}

let arr=UnsafePointer（buf）.advanced（by:off）
设msk=arr.withMemoryRebound（to:UInt32.self，容量：1）{p in
返回p[0]。bigEndian&0x7fffffff
}

这可能就是您要寻找的：

let arr = UnsafePointer<UInt8>(buf).advanced(by: off)
let msk = arr.withMemoryRebound(to: UInt32.self, capacity: 1) { p in
    return p[0].bigEndian & 0x7fffffff
}