Ios 如何在do block内使用投掷？

如果可能的话，我想从do块内抛出错误

我有一个函数getWeatherBy，它被签名为抛出函数。我在应用程序中其他地方的代码取决于此。在这个函数的内部有一个JSONDecoder.decode，它抛出函数本身，在do块的内部有一个。然而，如果JSONDecoder有错误，我想从getWeatherBy抛出错误，但是由于抛出是在JSONDecoder内部发生的，所以它在那里被捕获

对不起，代码太乱了。我还是一个新手，任何关于如何使这段代码更好的想法都是非常受欢迎的

func getWeatherBy(city: String, completion: ((WeatherRecord) -> ())?) throws {
        let trimmedCityName = (city as NSString).replacingOccurrences(of: " ", with: "+")
        
        let url = URL(string: "https://api.openweathermap.org/data/2.5/weather?q=\(trimmedCityName.lowercased())&appid=\(self.OpenWeatherAPIkey)&units=metric")
        guard url != nil else { return }
        print(url!)

        let networkTask: URLSessionDataTask = URLSession.shared.dataTask(with: url!) {
            (data, response, error) in
            guard let data = data else { return }
            
            do {
                let decoded = try JSONDecoder().decode(WeatherData.self, from: data)
                if (decoded.main != nil) {
                    if (decoded.coord?.lat != nil) {
                        DispatchQueue.main.async {
                            let record = WeatherRecord(temperature: Float(decoded.main!.temp), date: Date(), coordinates: CLLocationCoordinate2D(latitude: decoded.coord!.lat, longitude: decoded.coord!.lon), distance: 0.0)
                            
                            if completion != nil {
                                completion!(record)
                                
                            }
                        }
                    }
                } else {
                    throw serviceError.cityNotFound
                }
                
                if (decoded.message != nil) {
                    print("Message: \(decoded.message!)")
                    
                    DispatchQueue.main.async {
                        if (String(describing: decoded.message!).contains("Your account is temporary blocked") == true) {
                            
                        }
                        
                        if (decoded.message! != "Nothing to geocode") || String(describing: decoded.message!).contains("Your account is temporary blocked") != false {
                            
                        }
                    }
                }
            } catch DecodingError.keyNotFound(let key, let context) {
                Swift.print("Could not find key \(key) in JSON: \(context.debugDescription)")
            } catch DecodingError.valueNotFound(let type, let context) {
                Swift.print("Could not find type \(type) in JSON: \(context.debugDescription)")
            } catch DecodingError.typeMismatch(let type, let context) {
                Swift.print("Type mismatch for type \(type) in JSON: \(context.debugDescription) \(context)")
            } catch DecodingError.dataCorrupted(let context) {
                Swift.print("Data found to be corrupted in JSON: \(context.debugDescription)")
            } catch let error as NSError {
                NSLog("Error in read(from:ofType:) domain= \(error.domain), description= \(error.localizedDescription)")
            }
        }

---

最常见的方法是添加带有/不带有新错误的错误

---

您不能立即从异步方法抛出

抛出的JSONDecoder位于异步回调中-即，如果抛出，它将异步完成。同步

getWeatherBy

函数不能抛出相同的错误。您可以做的是将错误作为参数传递给完成闭包。查看作为传递成功值或错误的一种方法，我看到了！非常感谢！您可以从异步函数中抛出，但它会稍后出现。这是Objective-C。Swift签名与

->Void

相同：

（）抛出->天气记录->Void

。

func getWeatherBy(city: String, completion: ((WeatherRecord? , Error?) -> ()))