Ios 如何通过按钮打开URL？

我有一个

UITextView

，在那里我输入了一些文本。我有一个

ui按钮

。我想单击按钮并打开我在

UITextView

中键入的文本应该出现的URL。我正在为IOS 7编写一个字典应用程序，当我想让人们翻译我的文本时，需要这个功能。我知道如何只打开URL，但我的文本应该显示在URL中的框中。有人能帮我编码吗

SozdikViewController.h
@interface SozdikViewController : UIViewController
@property (strong, nonatomic) IBOutlet UITextView *textView1;
@property (weak, nonatomic) IBOutlet UIButton *Button_Ask;
-(IBAction)ask;
@end

这是我的SozdikViewController.m文件

#import "SozdikViewController.h"
@interface SozdikViewController ()
@end
@implementation SozdikViewController
-(IBAction)ask
{
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"http://www.audaru.kz/?product=SoylemMT&word="]];
}
...

@end

---

如果我理解正确，您只需要翻译在UITextField中键入的文本。所以你必须简单使用

[[UIApplication sharedApplication] openURL:[NSURL URLWithString: [NSString stringWithFormat:@"http://www.audaru.kz/?product=SoylemMT&word=%@", textView1.text]]];

并将

%@

移动到url中的正确位置。 希望有帮助

像这样试试

//Append your word in the text field to the url

 NSString *urlString = [NSString stringWithFormat:@"http://www.audaru.kz/?product=SoylemMT&word=%@",textField.text];            
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:urlString]];

---

您可以通过以下方式从文本视图获取URL：

NSString *urlString = self.textView.text;

然后，您可以通过以下方式打开url：

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:urlString]];

---

我在代码中加入了注释来解释每个步骤，但是您应该能够使用

stringWithFormat:

构造一个

NSString*

，并将您的URL（

http://www.audaru.kz/?product=SoylemMT&word=%@

）和

[[self textview 1]text]

然后，您只需将其传递给

NSURL*

的实例，并使用

[[UIApplication sharedApplication]canOpenURL:][/code>检查是否可以打开URL。检查完后，如果为真，则可以使用
[[UIApplication sharedApplication]openURL:][/code>打开它。还要确保所有的
IBOutlets
链接正确，否则它将无法执行任何操作

SozdikViewController.h

// Start of interface file
@interface SozdikViewController : UIViewController

// Property declarations
// Note the lower cases at the beginning of the property variable names
@property (strong, nonatomic) IBOutlet UITextField *textView1;
@property (weak, nonatomic) IBOutlet UIButton *buttonAsk; 

// Method declarations
- (IBAction)ask;

@end
// end of interface file

SozdikViewController.m

// Start of implementation file
#import "SozdikViewController.h"

// You are clearly not using the class extention so why is it there
// Removed it as it is pointless being there if you aren't using it

@implementation SozdikViewController

// Synthesize is done for you automatically

- (IBAction)ask
{
    // We are going to do it like everyone says but add a few checks in
    // First lets check to make sure that the textView1s text isn't nil or an empty string
    if([[self textView1] text] != nil && ![[[self textView1] text] isEqualToString:@""]) {
        // Construct the URL with the word that has been passed in
        NSURL *urlString = [NSURL URLWithString:[NSString stringWithFormat:@"http://www.audaru.kz/?product=SoylemMT&word=%@", [[self textView1] text]]];
        // Next check to make sure that the URL can actually be opened
        // otherwise forget about it as it would be pointless.
        if([[UIApplication sharedApplication] canOpenURL:urlString]) {
            // We can open it so lets open it
        [[UIApplication sharedApplication] openURL:urlString];
        } else {
            // else do something to tell the use it can't be done.
        }
    }
}

@end
// end of implementation file

NSString*url=self.textView1.text；我强烈建议不要把所有这些都放在一条线上。您应该首先获取文本，将其转换为URL，然后打开它。如果按原样编写代码，那么代码很难阅读。@LordZsolt我试着把代码写成作者的问题。是的，这是真的。虽然如果他的编码风格有点怪异，你不应该建议他继续使用这种编码风格，但当PM/老板告诉他要改变时，他很难改变。
// Start of implementation file
#import "SozdikViewController.h"

// You are clearly not using the class extention so why is it there
// Removed it as it is pointless being there if you aren't using it

@implementation SozdikViewController

// Synthesize is done for you automatically

- (IBAction)ask
{
    // We are going to do it like everyone says but add a few checks in
    // First lets check to make sure that the textView1s text isn't nil or an empty string
    if([[self textView1] text] != nil && ![[[self textView1] text] isEqualToString:@""]) {
        // Construct the URL with the word that has been passed in
        NSURL *urlString = [NSURL URLWithString:[NSString stringWithFormat:@"http://www.audaru.kz/?product=SoylemMT&word=%@", [[self textView1] text]]];
        // Next check to make sure that the URL can actually be opened
        // otherwise forget about it as it would be pointless.
        if([[UIApplication sharedApplication] canOpenURL:urlString]) {
            // We can open it so lets open it
        [[UIApplication sharedApplication] openURL:urlString];
        } else {
            // else do something to tell the use it can't be done.
        }
    }
}

@end
// end of implementation file