Iphone迭代NSString的子字符串

我希望在NSString中找到所有出现的子字符串，并逐一迭代以对该NSString进行一些更改。我该怎么做呢？

怎么样

// find first occurrence of search string in source string
NSRange range = [sourceString rangeOfString:@"searchString"];
while(range.location != NSNotFound)
{
    // build a new string with your changed values

    range = [sourceString rangeOfString:@"searchString" options:0 range:NSMakeRange(range.location + 1, [sourceString length] - range.location - 1)];
}

或者只是

[sourceString stringByReplacingOccurrencesOfString:searchString withString:targetString];

---

如果您想将searchString更改为源字符串中所有位置的相同值。

我会选择以下内容：

// Setup what you're searching and what you want to find
NSString *string = @"abcabcabcabc";
NSString *toFind = @"abc";

// Initialise the searching range to the whole string
NSRange searchRange = NSMakeRange(0, [string length]);
do {
    // Search for next occurrence
    NSRange range = [string rangeOfString:toFind options:0 range:searchRange];
    if (range.location != NSNotFound) {
        // If found, range contains the range of the current iteration

        // NOW DO SOMETHING WITH THE STRING / RANGE

        // Reset search range for next attempt to start after the current found range
        searchRange.location = range.location + range.length;
        searchRange.length = [string length] - searchRange.location;
    } else {
        // If we didn't find it, we have no more occurrences
        break;
    }
} while (1);

---

你可能想看看

查找字符和子字符串

– rangeOfCharacterFromSet:
– rangeOfCharacterFromSet:options:
– rangeOfCharacterFromSet:options:range:
– rangeOfString:
– rangeOfString:options:
– rangeOfString:options:range:
– rangeOfString:options:range:locale:
– enumerateLinesUsingBlock:
– enumerateSubstringsInRange:options:usingBlock:

– componentsSeparatedByString:
– componentsSeparatedByCharactersInSet:
– stringByTrimmingCharactersInSet:
– substringFromIndex:
– substringWithRange:
– substringToIndex:

分割字符串

– rangeOfCharacterFromSet:
– rangeOfCharacterFromSet:options:
– rangeOfCharacterFromSet:options:range:
– rangeOfString:
– rangeOfString:options:
– rangeOfString:options:range:
– rangeOfString:options:range:locale:
– enumerateLinesUsingBlock:
– enumerateSubstringsInRange:options:usingBlock:

– componentsSeparatedByString:
– componentsSeparatedByCharactersInSet:
– stringByTrimmingCharactersInSet:
– substringFromIndex:
– substringWithRange:
– substringToIndex:

---

如果要进行更改，可以使用：

-（NSString*）stringByReplacingOccurrencesOfString:（NSString*）目标与string:（NSString*）替换

但如果这不符合您的需要，请尝试以下方法：

-（void）EnumerateStringsRange:（NSRange）范围选项：（NSStringEnumerationOptions）使用block选择：（void（^）（NSString*substring，NSRange substringRange，NSRange enclosuringRange，BOOL*stop））block

在@TheEye上展开，我做了以下准备：

@interface NSString (EnumerateOccurancesOfString)

- (void)enumerateOccurancesOfString:(NSString *)string usingBlock:(void (^)(NSRange substringRange, BOOL *stop))block;

@end

-

---

你的意思是如果你有

@“abcabc”

你想迭代所有

@“abc”

s吗？还可以使用：NSArray*stringArray=[myString componentsSeparatedByString:@“mySubString”]；我按错了键，我的答案一开始是不完整的：-）由分离的组件发送。。。删除搜索字符串的所有匹配项，而不进行迭代…请参阅HelmiB所述的文档。这很复杂，有一种方法：

-（void）EnumerateSubstringsRange:（NSRange）范围选项：（NSStringEnumerationOptions）opts usingBlock:（void（^）（NSString*substring，NSRange substringRange，NSRange ENCOLLINGRANGE，BOOL*stop））块

。在搜索了很多之后非常有用。谢谢。+1Matt的方法允许您更改字符串，因为它没有被枚举。