Iphone 二进制表达式的无效操作数（'double'和'double'）目标c问题

二进制表达式“double”和“double”的操作数无效目标c问题

-(double)performOperationWith:(double *)operand1 
                         And:(double *)operand2 {

    double result = 0.0;

    result = operand1 + operand2;

    return result;
}

只需拆下*：

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它们是指针，因此您应该取消对它们的引用：

result = *operand1 + *operand2;

或更改功能参数：

-(double)performOperationWith:(double )operand1 And:(double )operand2 {...}

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我是一名Android程序员，我想学习iOS。我忘了指针

-(double)performOperationWith:(double )operand1 And:(double )operand2 {...}