Iphone a「+&引用;登录电子邮件地址
我需要在服务器上提交一个带有“Iphone a「+&引用;登录电子邮件地址,iphone,objective-c,iphone-sdk-3.0,Iphone,Objective C,Iphone Sdk 3.0,我需要在服务器上提交一个带有“+”签名和验证的电子邮件地址。但服务器会收到类似“aaa”的电子邮件+bbb@mail.com“作为”aaabbb@mail.com” 我以POST请求的形式发送所有数据,代码如下 NSURL* url = [NSURL URLWithString:[NSString stringWithFormat:@"%@%@", url, @"/signUp"]]; NSString *post = [NSString stringWithFormat:@"&ema
+
”签名和验证的电子邮件地址。但服务器会收到类似“aaa”的电子邮件+bbb@mail.com
“作为”aaabbb@mail.com
”
我以POST请求的形式发送所有数据,代码如下
NSURL* url = [NSURL URLWithString:[NSString stringWithFormat:@"%@%@", url, @"/signUp"]];
NSString *post = [NSString stringWithFormat:@"&email=%@&userName=%@&password=%@",
user.email,
user.userName,
user.password];
NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:NO];
NSData* data = [self sendRequest:url postData:postData];
编码前的post变量具有值
&email=aaa+bbb@gmail.coma&userName=Asdfasdfadsfadsf&password=sdfasdf
编码后,它是相同的
&email=aaa+bbb@gmail.coma&userName=Asdfasdfadsfadsf&password=sdfasdf
我用于发送请求的方法类似于以下代码:
-(id) sendRequest:(NSURL*) url postData:(NSData*)postData {
// Create request
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
NSString *postLength = [NSString stringWithFormat:@"%d",[postData length]];
[request setURL:url];
[request setHTTPMethod:@"POST"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Current-Type"];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setHTTPBody:postData];
NSURLResponse *urlResponse;
NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:&urlResponse error:nil];
[request release];
return data;
}
HTTP服务器正在取消将
+
替换为空间
您需要通过调用
CFURLCreateStringByAddingPercentEscapes将+
转义为%2B
,HTTP服务器正在将+
取消转义为空间
您需要通过调用cfurlcreateStringByAddingPercentesEscapes将+
转义为%2B
,您需要对加号进行URL编码。它必须变成%2B
,接收者才会认为它是加号。您需要对加号进行URL编码。它必须变成%2B
,接收者才会认为它是加号。电子邮件、用户名和密码需要通过-stringByAddingPercentEscapesUsingEncoding:
转义
NSString *post = [NSString stringWithFormat:@"&email=%@&userName=%@&password=%@",
[user.email stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding],
...
但是,这不会转义+
,因为它是一个有效的URL字符。您可以使用更复杂的cfurlCreateStringByAddingPercentescape
,或者为了简单起见,只需将所有+
替换为%2B
:
NSString *post = [NSString stringWithFormat:@"&email=%@&userName=%@&password=%@",
[[user.email stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]
stringByReplacingOccurrencesOfString:@"+" withString:@"%2B"], ...
电子邮件、用户名和密码需要通过-stringByAddingPercentEscapesUsingEncoding:
转义
NSString *post = [NSString stringWithFormat:@"&email=%@&userName=%@&password=%@",
[user.email stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding],
...
但是,这不会转义+
,因为它是一个有效的URL字符。您可以使用更复杂的cfurlCreateStringByAddingPercentescape
,或者为了简单起见,只需将所有+
替换为%2B
:
NSString *post = [NSString stringWithFormat:@"&email=%@&userName=%@&password=%@",
[[user.email stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]
stringByReplacingOccurrencesOfString:@"+" withString:@"%2B"], ...
我不是100%确定,但您可能想通过添加百分比转义usingencoding:
@greg:Wow,这是一个方法名。我不是100%确定,但您可能想查看NSString的stringByAddingPercentEscapesUsingEncoding:
@greg:Wow,这是一个方法名。