Java MongoDB聚合差异在天数差异匹配时匹配

如果天数=一个数字和$acceptedDate之间的差值大于$liveDate-x天，则此聚合的变化会是什么，以获得结果或项目

    AggregationOperation redact = new AggregationOperation() {
        @Override
        public DBObject toDBObject(AggregationOperationContext aggregationOperationContext) {
        Map<String, Object> map = new LinkedHashMap<>();
        map.put("if",  BasicDBObject.parse("{'$gte':[{'$subtract':[{'$ifNull':['$acceptedDate', 
{'$date':" + System.currentTimeMillis() + "}]},'$lastVisit' **here minus x days **]},1296000000]}}")); //and the difference is 10 days
        map.put("then", "$$KEEP");
        map.put("else", "$$PRUNE");
        return new BasicDBObject("$redact", new BasicDBObject("$cond", map));
    };

    Aggregation aggregation = Aggregation.newAggregation(redact);

    List<FactoryAcceptance> results = mongoTemplate.aggregate(aggregation, FactoryAcceptance.class, FactoryAcceptance.class).getMappedResults();

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基本上，一个参数是作为变量传递的，他们希望在天内匹配差异，比如说显示差异为5天的记录，但在这种情况下，lastVisit应该是负5天。

您可以使用下面的查询

BasicDBObject.parse("
  {'$eq':[
     {'$subtract':[
       {'$ifNull':['$acceptedDate',{'$date':" + System.currentTimeMillis() + "}]},
       {'$subtract':['$lastVisit', 216000000]} // 5 days
     ]}, 
     432000000 // 10 days
  ]}"
);

与gte相比，它不是$eq吗？因为它与特定的天数相匹配？