如何将简单Curl调用转换为Java HttpURLConnection

有效的简单curl调用是： 卷曲https://api.github.com/search/repositories\？q\=无功

我现在在Java中尝试的是什么

                URL url = new URL("https://api.github.com/search/repositories\\?q\\=reactive");
    HttpURLConnection con = (HttpURLConnection) url.openConnection();
    con.setRequestMethod("GET");
    con.setRequestProperty("Content-Type", "application/json");
    con.setConnectTimeout(5000);
    con.setReadTimeout(5000);

    int isError = con.getResponseCode();
    System.out.println("Error code is " + isError);

    InputStream error = con.getErrorStream();

    System.out.println("Error is " + error.toString() + " \n");

    BufferedReader in = new BufferedReader(
        new InputStreamReader(con.getErrorStream()));
    String inputLine;
    StringBuffer content = new StringBuffer();
    while ((inputLine = in.readLine()) != null) {
        content.append(inputLine);
    }
    System.out.println("Error: " + content.toString());

错误代码：404

错误消息：错误：{消息：未找到，文档\u url:https://developer.github.com/v3}

为什么我用那种方式搜索它时却找不到呢

---

谢谢大家!

您在java代码中使用的URL与用于curl的转义字符错误。删除转义字符并使用urlhttps://api.github.com/search/repositories?q=reactive:

输出：

OK

error.toString不会打印错误消息。考虑读取流并在这里发布错误消息。

OK