Java Spring MVC-将空日期作为参数传递

我正在尝试在我的一个控制器上实现一个过滤器

这是控制器

@RequestMapping(value =  "", method = RequestMethod.GET)
    public String listSpots(ModelMap model, @RequestParam (value= "page", required = false) Integer page,
                            @RequestParam (value="numeroPosto", required = false) Integer numeroPosto,
                            @RequestParam(value="nomePosto", required = false) String nomePosto,
                            @RequestParam(value="occupied", required = false) Integer occupied,
                            @RequestParam(value="idPark", required = false) Integer idPark,
                            @RequestParam(value="idPiano", required = false) Integer idPiano,
                            @RequestParam(value="dateTime", required = false) Date dateTime) {

        if (page == null) {
            currentPage = 1;
        } else {
            currentPage = page;
        }
        int offset = (currentPage - 1) * elementsPerPage;
        //creo la mappa dei criteri
        Map<String, Object> criteri = new HashMap<String, Object>();
        criteri.put("numeroPosto", numeroPosto);
        criteri.put("nomePosto", nomePosto);
        criteri.put("occupied", occupied);
        Park park = null;
        Piano piano = null;
        if(idPark!=null){
            park = parkService.findById(idPark);
        }
        if(idPiano!=null){
            piano = pianoService.findById(idPiano);
        }
        criteri.put("park", park);
        criteri.put("piano", piano);
        criteri.put("dateTime", dateTime);
        int numOfRows = postoService.showSpotsCount(criteri);
        List<Posto> posti = postoService.showSpots(offset, criteri);
        List<Posto> posto = new ArrayList<Posto>(posti.size());
        for (Posto javaBean : posti){
            Date date = new Date();
            Date start = new Timestamp(date.getTime());
            Date end = javaBean.getDateTime();
            DateTime st = new DateTime(start);
            DateTime en = new DateTime(end);
            Long hours = postoService.getHours(st, en);
            Long minutes = postoService.getMinutes(st, en);
            javaBean.setHours(hours);
            javaBean.setMinutes(minutes);
            posto.add(javaBean);
        }
        int pages = 1+(numOfRows / elementsPerPage);
        String pageTitle = messageSource.getMessage("spot.list", null, locale);
        model.addAttribute("pageTitle", pageTitle);
        model.addAttribute("cssActiveSpots", cssActiveSpots);
        model.addAttribute("posto", posto);
        model.addAttribute("currentPage", currentPage);
        model.addAttribute("pages", pages);
        model.addAttribute("numOfRows", numOfRows);
        return path + "/posti";
    }

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我能解决这个问题吗？

只要将它添加到控制器中，它就会工作

@InitBinder
public void initBinder(WebDataBinder binder) {
    SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd"); 
    // change the format according to your need.
    dateFormat.setLenient(false);

    binder.registerCustomEditor(Date.class, new CustomDateEditor(dateFormat, true));
}

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你试过跳过这个参数吗？如果我跳过它，打算删除这个参数，一切正常。。。如果我在其中输入了正确的日期，它也可以工作。我不是说从控件中删除。只是不要通过它。您将required设置为false。如果将“”作为日期传递，则会出现错误，因为“”无法转换为日期对象，因为在筛选结果时，我的表单中有它，但它不会出现在每个视图中。我的意思是，如果我跳过required=false，我必须在我向控制器发出的每个请求中设置日期时间，这不是我们需要的。是否有方法分析“”值？您可以将日期更改为字符串，并在控制器中使用SimpleDataFormat对其进行分析。需要有人接受此答案，因为它只适用于我。非常感谢！

@InitBinder
public void initBinder(WebDataBinder binder) {
    SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd"); 
    // change the format according to your need.
    dateFormat.setLenient(false);

    binder.registerCustomEditor(Date.class, new CustomDateEditor(dateFormat, true));
}