动态键值对的JSON到JAVA POJO
我必须创建以下JSON的POJO类,问题是键p_d具有动态名称的变量,如s_t、n_t、n_p等。真正的JSON很大,我只面临这一部分的问题,我共享了部分JSON。 我正在使用jackson进行解析动态键值对的JSON到JAVA POJO,java,json,Java,Json,我必须创建以下JSON的POJO类,问题是键p_d具有动态名称的变量,如s_t、n_t、n_p等。真正的JSON很大,我只面临这一部分的问题,我共享了部分JSON。 我正在使用jackson进行解析 { "flag": true, "flag2": false, "r_no": [ { "room_type": 250067, "no_of_rooms": 1, "no_of_children": 1, "no_of_adult
{
"flag": true,
"flag2": false,
"r_no": [
{
"room_type": 250067,
"no_of_rooms": 1,
"no_of_children": 1,
"no_of_adults": 2,
"description": "Executive Room, 1 King Bed, Non Smoking",
"children_ages": [
8
]
},
{
"room_type": 250067,
"no_of_rooms": 1,
"no_of_children": 0,
"no_of_adults": 2,
"description": "Executive Room, 1 King Bed, Non Smoking"
}
],
"r_code": "abc",
"r_key": "123",
"p_d": {
"s_t": [
{
"name": "xyz",
"cur": "INR"
},
{
"name": "xyz1",
"cur": "INR"
}
],
"n_t": [
{
"name": "xyz2",
"cur": "INR"
}
],
"n_p": [
{
"name": "xyz5",
"cur": "INR"
}
]
},
"cur": "INR"
}
对于动态关键点,请使用
地图:
ObjectMapper mapper=new ObjectMapper();
Map parsed=mapper.readValue(json,
新类型引用(){});
您的试用码在哪里@Surajpublic类PD{@JsonProperty(“s_t”)private List sT=new ArrayList();@JsonProperty(“n_t”)private List nT=new ArrayList();@JsonProperty(“n_p”)private List nP=new ArrayList();@JsonIgnore private Map additionalProperties=new HashMap();setter getter}这里的变量名是静态的,但需要动态变量。请不要将您的代码放在注释编辑器中进行同样的操作,但JSON很大,我只分享了我面临的部分问题ObjectMapper mapper=new ObjectMapper();请尝试{responseDto=mapper.readValue(response,com.HSR.class);}catch(JsonGenerationException e){e.printStackTrace();}