Java J2EE与httppostservlet
我在谷歌上搜索了很多,尝试了所有主要针对PHP的解决方案,但都不起作用。我试图将POST参数发送到J2EEServlet,但servlet并没有接收到参数,尽管我是通过附加URL(GET)来发送参数,以便能够接收数据 这是密码Java J2EE与httppostservlet,java,angular,typescript,servlets,ionic2,Java,Angular,Typescript,Servlets,Ionic2,我在谷歌上搜索了很多,尝试了所有主要针对PHP的解决方案,但都不起作用。我试图将POST参数发送到J2EEServlet,但servlet并没有接收到参数,尽管我是通过附加URL(GET)来发送参数,以便能够接收数据 这是密码 import { Component } from '@angular/core'; import { IonicPage, NavController, NavParams } from 'ionic-angular'; import { Http,
import { Component } from '@angular/core';
import { IonicPage, NavController, NavParams } from 'ionic-angular';
import { Http, Headers, RequestOptions } from '@angular/http';
import 'rxjs/Rx';
@IonicPage()
@Component({
selector: 'page-login',
templateUrl: 'login.html',
})
export class LoginPage {
userName: string;
password: string;
constructor(public navCtrl: NavController, public navParams: NavParams,
public http: Http) {
}
login() {
var headers = new Headers({ 'Content-Type': 'application/json' });
let options = new RequestOptions({ headers: headers });
let devicecode = '1-001-001-009-1';
let postParams = {
loginid: this.userName,
password: this.password,
devicecode: devicecode
}
this.http.post("http://localhost:8092/OCWebService/LoginOSO", postParams
, options)
.subscribe(data => {
console.log(data);
alert(data);
}, error => {
console.log(error);// Error getting the data
});
}
}
以下是Servlet代码:
protected void processRequest(HttpServletRequest request,
HttpServletResponse response)
throws ServletException, IOException {
response.setHeader("Access-Control-Allow-Origin", "*");
response.setHeader("Access-Control-Allow-Credentials", "true");
response.setHeader("Access-Control-Allow-Methods", "GET,PUT,POST,DELETE");
response.setContentType("text/html;charset=UTF-8");
BufferedReader bf = request.getReader();
String userName = request.getParameter("loginid");
String password = request.getParameter("password");
String deviceCode = request.getParameter("devicecode");
}
注意:我是离子2的新手。参数(request.getParameter()
)仅用于应用程序/x-www-form-urlencoded
数据或参数。您正在发送JSON
为了解决这个问题,您可以从请求输入流中提取JSON,或者自己解析它。为此,您需要使用类似Jackson的库。比如说
InputStream in = request.getInputStream();
MyPojo pojo = new ObjectMapper().readValue(in, MyPojo.class);
ObjectMapper
是一个Jackson类。您应该发布servlet代码的堆栈跟踪谢谢。工作得很有魅力!我使用了第一种解决方案。