用多个分隔符检查段落的部分。（JAVA）

如果这是给定的输入：

未经审查的输入：

Name: John Doe

Email: john@school.edu

Phone: 456-832-7180 

这就是我想要的：

The newly Censored input:

Name: J*** **e

Email: j***@s*****.edu

Phone: XXX-XXX-7180

以下是给我的指示： 在审查信息时，我们将使用以下格式：

“类型：此处的信息\n”

○ 我们要筛选的类型可以是“姓名”、“电子邮件”或“电话”

○ “Type”和“Type”之间总是有一个冒号和一个空格 “信息在这里”

○ 每行将以换行符（\n）结尾

我试着使用数组列表和子字符串来隔离名字和姓氏，但不知怎么的，还是做不到。 问题是，用户可以只输入姓名或电话，也可以输入全部三个或任意两个。这让人非常恼火。我的if语句不起作用，即使我能够审查它

这就是我得到的：

            System.out.println("Please enter the phrase you would like to censor information from: ");

            while (true) {

                // Obtain a line from the user
                String temp = scanner.nextLine();

                if (!passage.isEmpty() && temp.isEmpty()) {
                    break;
                } else if (passage.isEmpty() && temp.isEmpty()) {
                    continue;
                }


                // Add the contents of temp into the phrase
                passage += temp;


                // Append a newline character to each line for parsing
                // This will separate each line the user enters
                // To understand how input is formatted in Part 3, please refer to the handout.
                passage += '\n';

            }

            // Print the uncensored passage
            System.out.println("Uncensored: ");
            System.out.println(passage);

            ArrayList<String> obj = new ArrayList<String>();
            String s[] = passage.split("/n");
            obj.addAll(Arrays.asList(s));

            String what = obj.get(0);
            String cens = "";
            if (what.substring(0, 1) == "N"){
                String whole = what.substring(6,what.length());
                int space = whole.indexOf(" ");
                String first = whole.substring(0,space);
                String last = whole.substring(space, whole.length());
                String fcen = first.substring(0,1);
                for (int i = 1; i < first.length(); i++){
                    fcen += "*";
                    cens += fcen;
                }

System.out.println（“请输入您希望从中审查信息的短语：”；
while（true）{
//从用户处获取一行
字符串温度=scanner.nextLine（）；
如果（！passion.isEmpty（）&&temp.isEmpty（））{
打破
}else if（passion.isEmpty（）&temp.isEmpty（））{
持续
}
//将temp的内容添加到短语中
通道+=温度；
//将换行符追加到每行以进行分析
//这将分隔用户输入的每一行
//要了解第3部分中输入的格式，请参阅讲义。
段落+='\n'；
}
//打印未经审查的段落
System.out.println（“未经审查：”）；
系统输出打印LN（通道）；
ArrayList obj=新的ArrayList（）；
字符串s[]=段落.split（“/n”）；
obj.addAll（Arrays.asList）；
字符串what=obj.get（0）；
字符串cens=“”；
如果（什么子字符串（0，1）=“N”）{
字符串整数=what.substring（6，what.length（））；
int-space=整数。indexOf（“”）；
String first=整个子字符串（0，空格）；
字符串last=whole.substring（空格，whole.length（））；
字符串fcen=first.substring（0,1）；
for（int i=1；i

在审查数据（掩码）之前，您需要检查类型并验证字符串

对于电子邮件，您可以通过（从）进行验证

对于电话号码：匹配正则表达式字符串即可

 Pattern p = Pattern.compile("^[0-9\\-]*$");
 Matcher m = p.matcher("111-444-5555");
 boolean b = m.matches();

名称类似：

Pattern p = Pattern.compile("^[\\p{L} .'-]+$");
Matcher m = p.matcher("Patrick O'Brian");
boolean b = m.matches();

---

Regex来自

我以您的代码为起点，创建了以下代码：

public static String censorName(String name) {

        // check validity
        if(!name.contains(" ")) {
            return "Invalid entry";
        }

        String censored = "";

        for (int i = 0; i < name.length(); i++) {
            if(i==0 || i== name.length()-1 || name.charAt(i)==' ') {
                censored+= name.charAt(i);
            }else {
                censored += "*";
            }
        }
        return censored;
    }

    public static String censorEmail(String email) {

        // check validity
        if(!email.contains("@")) {
            return "Invalid entry";
        }

        String censored = "";

        for (int i = 0; i < email.length(); i++) {
            if(i==0 || i >= email.indexOf(".") || email.charAt(i)=='@' || email.charAt(i-1)=='@') {
                censored+= email.charAt(i);
            }else {
                censored += "*";
            }
        }
        return censored;
    }

    public static String censorPhone(String phone) {

        // check validity
        if(!phone.contains("-")) {
            return "Invalid entry";
        }

        String censored = "";

        for (int i = 0; i < phone.length(); i++) {
            if(i > phone.lastIndexOf("-") || phone.charAt(i)=='-') {
                censored+= phone.charAt(i);
            }else {
                censored += "X";
            }
        }
        return censored;
    }

    public static void main(String[] args) {

        // place your code here...
        String passage  ="Name: John Doe\n" + 
                "Email: john@school.edu\n" + 
                "Phone: 456-832-7180";

        // Print the uncensored passage
        System.out.println("Uncensored: ");
        System.out.println(passage);
        System.out.println();
        ArrayList<String> obj = new ArrayList<String>();
        String s[] = passage.split("\n"); // was wrong way
        obj.addAll(Arrays.asList(s));


        String name  = "", email="", phone="";
        for (String what : obj) {
            if (what.charAt(0) == 'N'){
                // censor name
                String uncensored  = what.substring(6,what.length());
                name = censorName(uncensored);
            }else if(what.charAt(0) == 'E') {

                String uncensored  = what.substring(7,what.length());
                email = censorEmail(uncensored);

            }else if(what.charAt(0) == 'P') {

                String uncensored  = what.substring(7,what.length());
                phone = censorPhone(uncensored);

            }
        }

        String censored  ="Name: "+name+"\n" + 
                "Email: "+email+"\n" + 
                "Phone: "+phone+"\n";

        System.out.println("Censored \n"+censored);


    } 

我注意到在拆分字符串时斜杠的方式是错误的，应该是

“\n”

。此外，我发现将审查拆分为单独的静态方法很有帮助，但是如果需要，也可以将该代码放在if语句中

---

希望这有帮助。

尝试发布代码问题的相关部分，以寻求调试帮助（“为什么这段代码不起作用？”）必须包括所需的行为、特定的问题或错误以及在问题本身中重现问题所需的最短代码。没有明确问题说明的问题对其他读者没有用处。请参阅：如何创建问题。使用链接改进问题-不要通过注释添加更多信息。谢谢！

what.substring（0，1）=“N”

-如何比较Java

段落中的字符串。拆分（“/N”）；

-这是否正确？

String what=obj.get（0）

每次都会得到相同的字符串我对java的了解不够，无法理解您在上面所做的事情，但感谢您抽出时间！我不知道为什么有人在没有发表评论的情况下投了反对票。

public static String censorName(String name) {

        // check validity
        if(!name.contains(" ")) {
            return "Invalid entry";
        }

        String censored = "";

        for (int i = 0; i < name.length(); i++) {
            if(i==0 || i== name.length()-1 || name.charAt(i)==' ') {
                censored+= name.charAt(i);
            }else {
                censored += "*";
            }
        }
        return censored;
    }

    public static String censorEmail(String email) {

        // check validity
        if(!email.contains("@")) {
            return "Invalid entry";
        }

        String censored = "";

        for (int i = 0; i < email.length(); i++) {
            if(i==0 || i >= email.indexOf(".") || email.charAt(i)=='@' || email.charAt(i-1)=='@') {
                censored+= email.charAt(i);
            }else {
                censored += "*";
            }
        }
        return censored;
    }

    public static String censorPhone(String phone) {

        // check validity
        if(!phone.contains("-")) {
            return "Invalid entry";
        }

        String censored = "";

        for (int i = 0; i < phone.length(); i++) {
            if(i > phone.lastIndexOf("-") || phone.charAt(i)=='-') {
                censored+= phone.charAt(i);
            }else {
                censored += "X";
            }
        }
        return censored;
    }

    public static void main(String[] args) {

        // place your code here...
        String passage  ="Name: John Doe\n" + 
                "Email: john@school.edu\n" + 
                "Phone: 456-832-7180";

        // Print the uncensored passage
        System.out.println("Uncensored: ");
        System.out.println(passage);
        System.out.println();
        ArrayList<String> obj = new ArrayList<String>();
        String s[] = passage.split("\n"); // was wrong way
        obj.addAll(Arrays.asList(s));


        String name  = "", email="", phone="";
        for (String what : obj) {
            if (what.charAt(0) == 'N'){
                // censor name
                String uncensored  = what.substring(6,what.length());
                name = censorName(uncensored);
            }else if(what.charAt(0) == 'E') {

                String uncensored  = what.substring(7,what.length());
                email = censorEmail(uncensored);

            }else if(what.charAt(0) == 'P') {

                String uncensored  = what.substring(7,what.length());
                phone = censorPhone(uncensored);

            }
        }

        String censored  ="Name: "+name+"\n" + 
                "Email: "+email+"\n" + 
                "Phone: "+phone+"\n";

        System.out.println("Censored \n"+censored);


    } 

Uncensored: 
Name: John Doe
Email: john@school.edu
Phone: 456-832-7180

Censored 
Name: J*** **e
Email: j***@s*****.edu
Phone: XXX-XXX-7180