Java 部署war spring失败-无法启动组件

我已经尝试将.WAR-spring部署到tomcat 9，但出现了一个错误-启动组件失败。

应用初始值设定项：

public class AppInitializer implements WebApplicationInitializer {

    public void onStartup(ServletContext container) throws ServletException {

        AnnotationConfigWebApplicationContext ctx = new AnnotationConfigWebApplicationContext();
        ctx.register(AppConfig.class);
        ctx.setServletContext(container);

        ServletRegistration.Dynamic servlet = container.addServlet(
                "dispatcher", new DispatcherServlet(ctx));

        servlet.setLoadOnStartup(1);
        servlet.addMapping("/");
    }
}

SpringBootwardDeployment应用程序：

@SpringBootApplication
public class SpringBootWarDeploymentApplication extends SpringBootServletInitializer {

    @Override
    protected SpringApplicationBuilder configure(SpringApplicationBuilder application) {
        return application.sources(SpringBootWarDeploymentApplication.class);
    }

    public static void main(String[] args) {
        SpringApplication.run(SpringBootWarDeploymentApplication.class, args);
    }   
}

AppConfig：

@Configuration
@EnableWebMvc
@ComponentScan(basePackages = "com.project.maven")
public class AppConfig extends WebMvcConfigurerAdapter {

    @Bean
    public ViewResolver viewResolver() {
        InternalResourceViewResolver viewResolver = new InternalResourceViewResolver();
        viewResolver.setViewClass(JstlView.class);
        viewResolver.setPrefix("/");
        viewResolver.setSuffix(".jsp");
        return viewResolver;
    }

    @Override
    public void addResourceHandlers(ResourceHandlerRegistry registry) {
        registry.addResourceHandler("/static/**").addResourceLocations("/static/");
        registry.addResourceHandler("**/**")
        .addResourceLocations("classpath:/META-INF/resources/"); // harus ada folder resources di webapp/WEB-INF/
    }       

    @Bean
    public MessageSource messageSource() {
        ResourceBundleMessageSource messageSource = new ResourceBundleMessageSource();
        messageSource.setBasename("messages");
        return messageSource;
    }   
}

在web.xml中，没有servlet配置。空配置。如何解决这个问题？当我放置我已经创建的url服务时，它没有找到，我有一个问题。当我在tomcat中部署war时，我必须把配置放进去吗？尽管如此，我的代码在部署之前运行良好。没问题

谢谢。

---

Bobby

您需要配置

web.xml

。使用以下参考代码：-

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">

<servlet>
    <servlet-name>appServlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextClass</param-name>
        <param-value>org.springframework.web.context.support.AnnotationConfigWebApplicationContext</param-value>
    </init-param>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>sample.traditional.config</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
    <servlet-name>appServlet</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

<!-- Disables Servlet Container welcome file handling. Needed for compatibility 
    with Servlet 3.0 and Tomcat 7.0 -->
<welcome-file-list>
    <welcome-file></welcome-file>
</welcome-file-list>

</web-app>

appServlet
org.springframework.web.servlet.DispatcherServlet
上下文类
org.springframework.web.context.support.AnnotationConfigWebApplicationContext
上下文配置位置
sample.traditional.config
1.
appServlet
/

有关更多配置，您可以遵循以下链接：-

---

即使是我，也在使用spring boot时收到了相同的Hello world错误消息。但是刚刚尝试了tomcat的最新版本（我使用了tomcat 8.5.23）。它就像魅力一样

我已经更改了web.xml，在“sample.traditional.config”中，我使用包配置进行了更改。这是真的吗？但还是同样的错误。。