当JAVA服务器（PC）通过蓝牙向错误的Android客户端发送消息时，该怎么办？

我正在开发一个应用程序，服务器（PC）通过蓝牙接受并处理Android客户端请求。我已经为连接的客户端创建了单独的线程。但是，当（例如）客户机A从服务器请求下一个数据时，服务器将数据发送给客户机B

以下是我的服务器代码片段：

public static void main(String[] args) throws IOException, SQLException, InstantiationException, IllegalAccessException {

    LocalDevice localDevice = LocalDevice.getLocalDevice();
    System.out.println("Address: "+localDevice.getBluetoothAddress());
    System.out.println("Name: "+localDevice.getFriendlyName());
    UUID uuid = new UUID("1101", true);

    String connectionString = "btspp://localhost:" + uuid +";name=Sample SPP Server";

    StreamConnectionNotifier streamConnNotifier = (StreamConnectionNotifier)Connector.open( connectionString );

    System.out.println("\nServer Started. Waiting for clients to connect...");

    while(true){
         ClientClass c = new ClientClass(streamConnNotifier.acceptAndOpen(), id);
         id++;
         clientList.add(c);
         Thread t = new Thread(c);
         t.start();  
    }
}

ClientClass声明代码：

public class ClientClass implements Runnable {
 private final StreamConnection _connection;
 private final int _id;

 public ClientClass(StreamConnection connection, int id){
    this._connection = connection;
    this._id = id;
 }

 public void run()
{
    try {

        RemoteDevice dev = RemoteDevice.getRemoteDevice(this._connection);
        System.out.println("Remote device address: "+dev.getBluetoothAddress());
        devName = dev.getFriendlyName(true);

        inStream = this._connection.openInputStream();
        outStream = this._connection.openOutputStream();

    while(true){
        BufferedReader bReader=new BufferedReader(new InputStreamReader(inStream));
        String lineRead=bReader.readLine();
        System.out.println(lineRead);
        questionInit.checkAnswer(lineRead);
        break;
    }
}

---

提前非常感谢。

ClientClass缺少run（）方法。好的。我编辑了我的代码，但这不是run（）方法中编写的唯一代码。并忽略其他方法，如questionInit的checkAnswer（）