Java 从xml文档获取html字符串

我有以下xml：

<version>
    <name>2.0.2</name>
    <description>
-Stop hsql database after close fist <br />
-Check for null category name before adding it to the categories list  <br />
-Fix NPE bug if there is no updates  <br />
-add default value for variable, change read bytes filter, and description of propertyFile  <br />
-Change HTTP web Proxy (the “qcProxy” field ) to http://web-proxy.isr.hp.com:8080  <br />
</description>
    <fromversion>>=2.0</fromversion>
</version>

---

我想使用Java返回描述标记字符串内容？

这是非常标准的Java XML解析，您可以在internet上的任何地方找到它，但在标准JDK中使用XPath时是这样的

String xml = "your XML";

// load the XML as String into a DOM Document object
DocumentBuilderFactory docFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder docBuilder = docFactory.newDocumentBuilder();
ByteArrayInputStream bis = new ByteArrayInputStream(xml.getBytes());
Document doc = docBuilder.parse(bis);

// XPath to retrieve the content of the <version>/<description> tag
XPath xpath = XPathFactory.newInstance().newXPath();
XPathExpression expr = xpath.compile("/version/description");
Node description = (Node)expr.evaluate(doc, XPathConstants.NODE);
System.out.println("description: " + description.getTextContent());

印刷品：

-Stop hsql database after close fist <br/>
-Check for null category name before adding it to the categories list  <br/>
-Fix NPE bug if there is no updates  <br/>
-add default value for variable, change read bytes filter, and description of propertyFile  <br/>
-Change HTTP web Proxy (the “qcProxy” field ) to http://web-proxy.isr.hp.com:8080  <br/>

编辑2

为了获得所有这些节点，您需要获得不同节点的节点集，并对其进行迭代，以执行与上面完全相同的操作

// XPath to retrieve the content of the <version>/<description> tag
XPath xpath = XPathFactory.newInstance().newXPath();
XPathExpression expr = xpath.compile("//description");
NodeList descriptionNode = (NodeList) expr.evaluate(doc, XPathConstants.NODESET);

List<String> descriptions = new ArrayList<String>(); // hold all the descriptions as String
Transformer transformer = TransformerFactory.newInstance().newTransformer();
transformer.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes");
for (int i = 0; i < descriptionNode.getLength(); ++i) {
    Node descr = descriptionNode.item(i);
    StringWriter sw = new StringWriter();
    transformer.transform(new DOMSource(descr), new StreamResult(sw));
    String description = sw.getBuffer().toString().replaceAll("</?description>", "");
    descriptions.add(description);
}
// here you can do what you want with the List of Strings `description`

---

请为这一要求提供适当的背景，因为它在当前状态下过于宽泛和模糊。谢谢到目前为止你试过什么？作为1000多名用户，您必须意识到，我们不会为您编码：-使用本文档的xsd，并使用任何XML解析实现，如apache xmlbeans、jaxb等。这将是最干净的方法。我使用了此代码，但问题是我在该标记中包含html代码。如果我尝试了你的代码，我只会得到第一行-关闭后停止hsql数据库。我有多个节点的描述标签。我需要一个解决方案将它们作为数组或任何其他数据结构返回。@FerasOdeh请参阅我的第二次编辑。如果下次你能直接解释你的整个问题，那就太酷了-

// XPath to retrieve the content of the <version>/<description> tag
XPath xpath = XPathFactory.newInstance().newXPath();
XPathExpression expr = xpath.compile("//description");
NodeList descriptionNode = (NodeList) expr.evaluate(doc, XPathConstants.NODESET);

List<String> descriptions = new ArrayList<String>(); // hold all the descriptions as String
Transformer transformer = TransformerFactory.newInstance().newTransformer();
transformer.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes");
for (int i = 0; i < descriptionNode.getLength(); ++i) {
    Node descr = descriptionNode.item(i);
    StringWriter sw = new StringWriter();
    transformer.transform(new DOMSource(descr), new StreamResult(sw));
    String description = sw.getBuffer().toString().replaceAll("</?description>", "");
    descriptions.add(description);
}
// here you can do what you want with the List of Strings `description`