Java 从.properties文件读取多个帐户的用户名和密码

我有以下问题。我有一个configuration.properties文件，我想在我的应用程序中读取它。其形式如下：

accountNames = account1, account2, account3
account1.userName = testUserName
account1.password = testUserPassword
account2.userName = secondTestUserName
account2.password = secondTestUserPassword
account2.userName = thirdTestUserName
account2.password = thirdTestUserPassword

如何读取所有帐户并在HashMap中存储配对用户名和用户密码？在我看来，我有一个二维数组。我对访问帐户的每个属性的代码特别感兴趣

编辑：我已将configuration.properties文件更改为以下格式：

userNames = testUserName, secondTestUserName, thirdTestUserName
testUserName = testUserPassword
secondTestUserName = secondTestUserPassword
thirdTestUserName = thirdTestUserPassword

处理此问题的代码如下所示：

    properties.load(new FileInputStream(configFilePath));
    for(String s : properties.getProperty("userNames").split(",")){
        clientCredentials.put(s.trim(), properties.getProperty(s.trim()));
    }

    //test:
    for(String s:clientCredentials.keySet()){
        System.out.println("Key: "+s+" & value: "+clientCredentials.get(s));
    }

    final Map<String, String> accounts = new HashMap<String, String>();
    final File pwdFile = new File("path to your user/password file");
    BufferedReader br = null;
    try
    {
        br = new BufferedReader(new FileReader(pwdFile));

        br.readLine();// you don't need the first line

        while (true)
        {
            String  line = br.readLine();
            if (line == null)
                break;//end of file have been reached

            final String user = line.split("=")[1].trim();

            line = br.readLine();
            if (line == null)// pwd is missing
                throw new Exception("Invalid pwd file");

            final String pwd = line.split("=")[1].trim();
            accounts.put(user, pwd);

        }

    }
    catch (final Exception e)
    {
        // add your own error handling code here
        e.printStackTrace();
    }
    finally
    {
        if (br != null)
            br.close();

    }

---

谢谢您的帮助。

如果您只关心用户名和密码，请尝试以下操作：

    properties.load(new FileInputStream(configFilePath));
    for(String s : properties.getProperty("userNames").split(",")){
        clientCredentials.put(s.trim(), properties.getProperty(s.trim()));
    }

    //test:
    for(String s:clientCredentials.keySet()){
        System.out.println("Key: "+s+" & value: "+clientCredentials.get(s));
    }

    final Map<String, String> accounts = new HashMap<String, String>();
    final File pwdFile = new File("path to your user/password file");
    BufferedReader br = null;
    try
    {
        br = new BufferedReader(new FileReader(pwdFile));

        br.readLine();// you don't need the first line

        while (true)
        {
            String  line = br.readLine();
            if (line == null)
                break;//end of file have been reached

            final String user = line.split("=")[1].trim();

            line = br.readLine();
            if (line == null)// pwd is missing
                throw new Exception("Invalid pwd file");

            final String pwd = line.split("=")[1].trim();
            accounts.put(user, pwd);

        }

    }
    catch (final Exception e)
    {
        // add your own error handling code here
        e.printStackTrace();
    }
    finally
    {
        if (br != null)
            br.close();

    }

---

此代码假定包含username的行后面紧跟着一行，该行的密码为前一行的username。

您对不同的值使用相同的名称。这是不正确的。但是如果一个帐户有两个或两个以上的属性，我如何独立访问它们？为什么不只配对用户名和密码，比如firstUserName=firstUserPassword？我想到了这一点，并找到了一个例子，但是如果每个帐户都有两个以上的属性，例如添加帐户的电子邮件，你能做什么？您如何管理这种情况？您希望如何将其存储在HashMap中？如果要使用第一列作为键，则不正确。对于常规文本文件，这是一种很好的做法，但对于configuration.properties，我希望从properties类的loadInputStream inStream方法开始。因为您希望在HashMap中使用它，所以使用此代码更简单、更快。否则，必须使用using Properties.load加载文件，然后迭代Properties对象的每个元素。第二个优点是，您可以在加载文件修剪时应用一些自定义格式，大写。。。