来自java的linuxshell命令
我正在尝试从Java运行Linux命令。该命令在命令行本身中运行得非常完美,但在Java中却没有。 命令行中的命令是来自java的linuxshell命令,java,linux,shell,Java,Linux,Shell,我正在尝试从Java运行Linux命令。该命令在命令行本身中运行得非常完美,但在Java中却没有。 命令行中的命令是 curl -H "Content-Type: text/plain" -d "$(printf '#Genes\nPIK3C2A\nPTEN\nUNC5B')" -X POST --url https://reactome.org/AnalysisService/identifiers/projection/ 来自Java的命令是 String $notifyMsg="\"$
curl -H "Content-Type: text/plain" -d "$(printf '#Genes\nPIK3C2A\nPTEN\nUNC5B')" -X POST --url https://reactome.org/AnalysisService/identifiers/projection/
来自Java的命令是
String $notifyMsg="\"$(printf '#Genes\nPIK3C2A\nPTEN\nUNC5B')\"";
String $reactome = "https://reactome.org/AnalysisService/identifiers/projection/";
String $notifyTitle= "\"Content-Type: text/plain\"";
String $command = "curl" + " " + "-H"+ " " + $notifyTitle + " "+ "-d " + $notifyMsg +" "+ "-X" + " " + "POST" + " " + " " + "--url" +" " + $reactome;
System.out.println("Command is: " + $command);
Process p=Runtime.getRuntime().exec($command);
p.waitFor();
System.out.println("Run Result " + p.exitValue() )
我被要求得到这样的输出
{"summary":{"token":"MjAxODAxMjMxNjQyMDZfNjcy","projection":true,"interactors":false,"type":"OVERREPRESENTATION","sampleName":"Genes","text":true},"expression":{"columnNames":[]},"identifiersNotFound":0,"pathwaysFound":51,"pathways":
但是我得到了0。谁能告诉我哪里不对吗?引用和逃避是你的敌人。最好的办法是完全避免它们。使用一个方法启动该过程,该方法允许您将各个参数作为单独的字符串传递,而无需将它们分开
Process p = new ProcessBuilder(
"curl",
"-H", "Content-Type: text/plain",
"-d", "#Genes\nPIK3C2A\nPTEN\nUNC5B",
"-X", "POST",
"--url", "https://reactome.org/AnalysisService/identifiers/projection/"
).start();
您的代码调用exitValue()
,这将为您提供进程的退出代码。要读取其输出,请从其
引用和逃避是你的敌人。最好的办法是完全避免它们。使用一个方法启动该过程,该方法允许您将各个参数作为单独的字符串传递,而无需将它们分开
Process p = new ProcessBuilder(
"curl",
"-H", "Content-Type: text/plain",
"-d", "#Genes\nPIK3C2A\nPTEN\nUNC5B",
"-X", "POST",
"--url", "https://reactome.org/AnalysisService/identifiers/projection/"
).start();
您的代码调用exitValue()
,这将为您提供进程的退出代码。要读取其输出,请从其
p.exitValue()
将为您提供进程的退出代码。它返回0,因为curl成功,退出代码为0
<>我会考虑在java中用这些方法来执行这些操作。p> p.exitValue()
将为您提供进程的退出代码。它返回0,因为curl成功,退出代码为0
<>我会考虑在java中用这些方法来执行这些操作。p> 这就是我的工作原理:
String notifyMsg = "#Genes\nPIK3C2A\nPTEN\nUNC5B";
String reactome = "https://reactome.org/AnalysisService/identifiers/projection/";
String notifyTitle = "Content-Type: text/plain";
Process p = new ProcessBuilder("curl", "-H", notifyTitle, "-d", notifyMsg, "-X", "POST", "--url", reactome).start();
p.waitFor();
try (Scanner scanner = new Scanner(new InputStreamReader(p.getInputStream()))) {
while (scanner.hasNextLine()) {
System.out.println(scanner.nextLine());
}
}
System.out.println("Run Result " + p.exitValue());
ProcessBuilder的vararg构造函数
内容类型
指令和-d
$(printf
是shell解释的东西,但Java不解释。只需在Java字符串文本中使用\n
即可获得新行我还添加了一些代码来读取输出。这就是我的工作原理:
String notifyMsg = "#Genes\nPIK3C2A\nPTEN\nUNC5B";
String reactome = "https://reactome.org/AnalysisService/identifiers/projection/";
String notifyTitle = "Content-Type: text/plain";
Process p = new ProcessBuilder("curl", "-H", notifyTitle, "-d", notifyMsg, "-X", "POST", "--url", reactome).start();
p.waitFor();
try (Scanner scanner = new Scanner(new InputStreamReader(p.getInputStream()))) {
while (scanner.hasNextLine()) {
System.out.println(scanner.nextLine());
}
}
System.out.println("Run Result " + p.exitValue());
ProcessBuilder的vararg构造函数
内容类型
指令和-d
$(printf
是shell解释的东西,但Java不解释。只需在Java字符串文本中使用\n
即可获得新行我还添加了一些代码来读取输出。
考虑使用JToice或Apache HTTP组件或其他java库。这里不需要使用CURL。为什么要通过启动<代码> CURL< /CUD>下载文件?当有许多本地java库来执行此操作时,请考虑使用JToSE或Apache HTTP组件或其他JA。va库。您不需要在此处使用curl。当有许多本机Java库可以执行此操作时,为什么要通过启动curl
来下载文件?