java中通过单套接字连接发送多个文件时出现EOF异常

我正在尝试通过java套接字发送多个文件。成功接收第一个文件后，它抛出EOFEException。我不知道出了什么问题。（所有文件均已成功从发送方发送）

发件人代码：

    sendToServer = new Socket(receiver,port);
    DataOutputStream out = new DataOutputStream(sendToServer.getOutputStream());

    for(File f: file_to_send){

        sendMessage = f.getName() + "\n"+ f.length() + "\n";
        out.writeUTF(sendMessage);

        FileInputStream requestedfile = new FileInputStream(f.getPath());
        System.out.println("file path: "+f.getPath());

        int count;
        byte[] buffer = new byte[8192];
        while ((count = requestedfile.read(buffer)) > 0)
        {
            out.write(buffer, 0, count);
        }

        System.out.println("File transfer completed!! voila! :)");
        requestedfile.close();
    }

    out.close();
    sendToServer.close();

System.out.println("File Count : " + fileCount);
for (int count =0; count<fileCount; count++){
            String fileName = dis.readUTF();
            int length = Integer.parseInt(fileName.split("\n")[1]);
            fileName = fileName.split("\n")[0];
            System.out.println("File Name : " + fileName);
            System.out.println("Length : " + length);
            System.out.println("File Data : ");
            FileOutputStream fos = new FileOutputStream(new File(fileName));
            int c;
            byte[] buffer = new byte[8192];
            while ((c = dis.read(buffer)) > 0)
            {
                fos.write(buffer, 0, c);
                fos.flush();
            }
            fos.close();
            System.out.println("\nFile received successfully!!! voila !! :)");               
        }

接收方代码：

    sendToServer = new Socket(receiver,port);
    DataOutputStream out = new DataOutputStream(sendToServer.getOutputStream());

    for(File f: file_to_send){

        sendMessage = f.getName() + "\n"+ f.length() + "\n";
        out.writeUTF(sendMessage);

        FileInputStream requestedfile = new FileInputStream(f.getPath());
        System.out.println("file path: "+f.getPath());

        int count;
        byte[] buffer = new byte[8192];
        while ((count = requestedfile.read(buffer)) > 0)
        {
            out.write(buffer, 0, count);
        }

        System.out.println("File transfer completed!! voila! :)");
        requestedfile.close();
    }

    out.close();
    sendToServer.close();

System.out.println("File Count : " + fileCount);
for (int count =0; count<fileCount; count++){
            String fileName = dis.readUTF();
            int length = Integer.parseInt(fileName.split("\n")[1]);
            fileName = fileName.split("\n")[0];
            System.out.println("File Name : " + fileName);
            System.out.println("Length : " + length);
            System.out.println("File Data : ");
            FileOutputStream fos = new FileOutputStream(new File(fileName));
            int c;
            byte[] buffer = new byte[8192];
            while ((c = dis.read(buffer)) > 0)
            {
                fos.write(buffer, 0, c);
                fos.flush();
            }
            fos.close();
            System.out.println("\nFile received successfully!!! voila !! :)");               
        }

---

接收文件的代码在读取第一个文件后不会停止，而是一直读取到流结束，将发送到同一文件的所有内容都写入

您需要跟踪已读取的字节数和/或仍需读取的字节数：

        int remainingBytes = length;
        while (remainingBytes > 0 && (c = dis.read(buffer, 0, Math.min(buffer.length, remainingBytes))) > 0)
        {
            remainingBytes -= c;
            fos.write(buffer, 0, c);
            // fos.flush(); this is not really necessary
        }

---

顺便说一下，对文件长度使用

int

将您的文件限制为最多2GB。如果这是一个问题，请使用

long

而不是

int

切勿在循环内刷新。它消除了任何可能存在的输出缓冲的好处。