在java中，如何从字符串数组中获取两个随机值之和？

我正在做一个纸牌对游戏，它从一个字符串数组中生成两个随机值。。我想知道的是如何从字符串数组中获取两个随机值的总和，以确定获胜者。这是密码

import java.util.*;

public class Cards {
private String suit;
private String face;
private String[] cardSuits;
private String[] cardFaces;
private Random ran;

public Cards() {
    ran = new Random();
    cardSuits = new String[] { "of Spade", "of Hearts", "of Diamonds",
            "of Clubs" };
    cardFaces = new String[] { "Ace", "2", "3", "4", "5", "6", "7", "8", "9",
            "10", "Jack", "Queen", "King" };

}

public String setPlayerCardSuit() {
    suit = cardSuits[ran.nextInt(4)];
    return suit;

}

public String setPlayerCardFace() {
    face = cardFaces[ran.nextInt(13)];
    return face;
}

public String setPlayerCardSuit2() {
    suit = cardSuits[ran.nextInt(4)];
    return suit;

}

public String setPlayerCardFace2() {
    face = cardFaces[ran.nextInt(13)];
    return face;
}

public String setCompCardSuit() {
    suit = cardSuits[ran.nextInt(4)];
    return suit;

}

public String setCompCardFace() {
    face = cardFaces[ran.nextInt(13)];
    return face;
}

public String setCompCardSuit2() {
    suit = cardSuits[ran.nextInt(4)];
    return suit;

}

public String setCompCardFace2() {
    face = cardFaces[ran.nextInt(13)];
    return face;
}

public void getResults() {
    System.out.println("Here are your cards: " + setPlayerCardFace() + " "
            + setPlayerCardSuit() + " and " + setPlayerCardFace2() + " "
            + setPlayerCardSuit2());
}

public void getCompCard() {
    System.out.println("Here's the computer's cards: " + setCompCardFace()
            + " " + setCompCardSuit() + " and " + setCompCardFace2() + " "
            + setCompCardSuit2());
}

}

下面是测试Cards类的代码：

import javax.swing.JOptionPane;

public class TestCards {
public static void main(String[] args) {
    Cards playerCards = new Cards();
    Cards computerCards = new Cards();

    int confirm, x = 1;
    while (x == 1) {
        JOptionPane.showMessageDialog(null,
                "Random Card game \nPlease press OK to Start Game",
                "Card Pair Game", JOptionPane.INFORMATION_MESSAGE);

        JOptionPane.showMessageDialog(
                null,
                "Here are your Cards: " + playerCards.setPlayerCardFace()
                        + " " + playerCards.setPlayerCardSuit() + " and "
                        + playerCards.setPlayerCardFace2() + " "
                        + playerCards.setPlayerCardSuit2()
                        + "\nThe Computer's Cards are: "
                        + computerCards.setCompCardFace() + " "
                        + computerCards.setCompCardSuit() + " and "
                        + computerCards.setCompCardFace2() + " "
                        + computerCards.setCompCardSuit2());


        confirm = JOptionPane.showConfirmDialog(null, "Game Ends. Again?",
                "Game Over", JOptionPane.YES_NO_OPTION);

        if (confirm != JOptionPane.YES_OPTION) {
            x = 2;
        }
    }
}
}

现在缺少的是确定获胜者的代码

我是java编程的初学者。。因此，如果你看到代码的不寻常用法，请耐心听我说：）

---

我试过迪伦的建议，但似乎无法奏效。。相反，他使用了他的想法，并将此代码添加到Cards类中

public int playerValues(){
    int temp = 0;
    if(face != cardFaces[0] && face != cardFaces[10] && face != cardFaces[11] && face != cardFaces[12]){
        temp = Integer.parseInt(face);
    }else if(face == cardFaces[0]){
        temp = 1;
    }else if(face == cardFaces[10]){
        temp = 11;
    }else if(face == cardFaces[11]){
        temp = 12;
    }else if(face == cardFaces[12]){
        temp = 13;
    }
    return temp;
}
public int computerValues(){
    int temp = 0;
    if(face != cardFaces[0] && face != cardFaces[10] && face != cardFaces[11] && face != cardFaces[12]){
        temp = Integer.parseInt(face);
    }else if(face == cardFaces[0]){
        temp = 1;
    }else if(face == cardFaces[10]){
        temp = 11;
    }else if(face == cardFaces[11]){
        temp = 12;
    }else if(face == cardFaces[12]){
        temp = 13;
    }
    return temp;
}

---

你有一个问题，不是所有的卡都是唯一的。两个玩家可以拥有相同的牌。它们甚至都可能是同一张牌

相反，您应该生成所有可能卡片的列表。我建议使用

卡
类。使用
Collections.shuffle
将其洗牌。这样所有的玩家都会有不同的牌

您需要比较一组卡片的规则。首先用英语定义它们，然后将它们翻译成代码。
我真的建议您的卡片是一个类或至少是一个枚举。然后把它们相加就有意义了

另外，请解释这两个

public String setCompCardFace()
public String setCompCardFace2()  //identical

你需要的是每个玩家都有一个和你开始时一样的卡片实例

public class Cards extends ArrayList<Card>

您不应该使用字符串数组来保存卡片面，而应该使用CardFace数组，该数组具有名称（用于显示）和值（用于计算面总和）。因为只有13个值，所以它应该是一个枚举：

public enum CardFace {
    ACE("Ace, 1),
    TWO("2", 2),
    ...
    KINK("King", 13);

    private String face;
    private int value;

    private CardFace(String face, int value) {
        this.face = face;
        this.value = value;
    }

    public String getFace() {
        return this.face;
    }

    public int getValue() {
        return this.value;
    }
}

使用
String.parseInt（）
方法将返回字符串中的数字。但是，你会和王牌，善良，女王，杰克有问题，因为他们不是一个数字。我建议创建一个声明，如：

if(!cardFaces[x].equals("Ace")&&!cardFaces[x].equals("Queen")&&!cardFaces[x].equals("King")&&!cardFaces[x].equals("Jack"))
  {
    int temp = cardFaces[x].parseInt();
   }
else if(cardFaces[x].equals("Ace")
{
  int temp = 1;
}
else if(cardFaces[x].equals("King") || cardFaces[x].equals("Queen") || cardFaces[x].equals("Jack"))
{
 int temp = 10;

我通过修改
TestCard
类而不是显示字符串数组中的两个随机值，成功地确定了获胜者。我更改了它，使其仅显示数组中的一个值。有了这些，我决定了谁是赢家。
似乎没有人谈论过获得组合，所以我将在这里讨论。如果你有什么不明白的地方，可以在这里发表评论

直接齐平-您需要一个for循环。

首先，您应该使用升序（1、2、3、4、5等）对玩家的牌数组进行排序。现在，从第一个条目开始检查，最低的

请注意，阵列卡仅存储输入整数的值

// Variables to store the current and previous cards.
int previous = 0;
int current = 0; 

cards = Arrays.sort(cards); // Sort cards into ascending order

boolean straightFlush = false;

for (i = 0; i < cards.length; i++) {
    current = cards[i];
    if (!current == cards[0]) { // If current is not the first card, execute the rest. You don't want random errors popping up, do you? :)
        // Check if it is the last card - a straight flush would then be present
        if (current == cards[cards.length - 1]) {
            straightFlush = true;
            break;
        }

        // Checks if current - 1 != previous or the current card is not consecutive to the previous card
        if (current - 1 != previous) {
            break;
        }
    }
...

//用于存储当前卡和以前卡的变量。
int-previous=0；
int电流=0；
卡片=数组。排序（卡片）；//将卡片按升序排序
布尔直插=假；
对于（i=0；i

那么如何比较牌数呢？如果是同花顺的话，在牌中找出最高的值

我很快会发布更多关于这个的信息。
你说的“总和”是什么意思对于字符串来说没有什么意义。你是在试图确定2的赢家吗？是的。如果我没有把我的问题说清楚，很抱歉。简而言之。我只是想知道谁赢了这场比赛。你还有一个更大的问题，那就是，在打印出牌的最后，每个玩家只有一张牌的记录。你能提供一个示例代码吗？我是这太新了。正如你所看到的，我是用我目前掌握的java知识编写代码的。这意味着我只能使用初学者学习的代码。请给我时间分析你建议的所有解决方案。我需要一个接一个地检查它们，因为给出的大多数代码对我来说都是新的。我会尝试你建议的这些代码。谢谢你post.我熟悉使用的代码。顺便说一句。我需要将x声明为整数吗？对于cardFaces[x]。等于（）x实际上应该是cardFaces等卡片的数字，因为x是
数组索引
。这意味着
cardFaces[0]=“Ace”cardFaces[1]=“2”
，等等。我尝试了你建议的解决方案，但我似乎无法让它工作，而是这样做了。
// Variables to store the current and previous cards.
int previous = 0;
int current = 0; 

cards = Arrays.sort(cards); // Sort cards into ascending order

boolean straightFlush = false;

for (i = 0; i < cards.length; i++) {
    current = cards[i];
    if (!current == cards[0]) { // If current is not the first card, execute the rest. You don't want random errors popping up, do you? :)
        // Check if it is the last card - a straight flush would then be present
        if (current == cards[cards.length - 1]) {
            straightFlush = true;
            break;
        }

        // Checks if current - 1 != previous or the current card is not consecutive to the previous card
        if (current - 1 != previous) {
            break;
        }
    }
...