Java 如何创建无需使用数组即可添加员工的工资表？

这是我的作业说明

实现一个名为Employee的类。一个雇员有一个名字，并得到一份薪水。每个发薪期，每位员工都会获得额外的奖金

在您的解决方案中，包括一个接受员工姓名和工资的构造函数。提供一个接受奖金金额并将其添加到工资中的mutator方法。提供必要的访问器方法以返回姓名、奖金发放前的工资、奖金以及奖金发放后的工资

我已经完成了所有这些，除了当我尝试添加另一个员工时，它只会覆盖变量并只打印最后添加的员工

这是我的密码：

    package employeetester;
import java.util.Scanner;

public class EmployeeTester {


    public static void main(String[] args) {
        String Employee = "";
        String Continue;
        String printChart;
        double salary = 0;
        double bonus = 0; 
        double totalSalary = 0;


        Scanner user_input = new Scanner( System.in );
        EmployeePayRoll epr = new EmployeePayRoll(Employee, salary);

        System.out.print("Would you like to add an employee to the pay roll? ");
          Continue = user_input.next();

        while (Continue.equalsIgnoreCase("yes") || Continue.equalsIgnoreCase("y")){

            System.out.println("What is the name of the employee?");
            Employee = user_input.next();
            epr.Employee(Employee);

            System.out.println("\nWhat is the salary of " + Employee + "? ");
            salary = user_input.nextDouble();
            epr.salary(salary);

            System.out.println("\nWhat is the bonus of " + Employee + "? ");
            bonus = user_input.nextDouble();
            epr.bonus(bonus);

            System.out.print("Would you like to add an employee to the pay roll? ");
            Continue = user_input.next();


            }

        System.out.println("\nWould you like to print out the pay roll chart? ");
            printChart = user_input.next();

            if (printChart.equalsIgnoreCase("Yes") || printChart.equalsIgnoreCase("y")){

                //EmployeePayRoll epr = new EmployeePayRoll(Employee, salary);
                epr.totalSalary(bonus);
                epr.printChart();
        }




    }

}

这是第二部分

package employeetester;


public class EmployeePayRoll {
    private String Employee;
    private double Salary;
    private double bonus;
    private double TotalSalary;

    public EmployeePayRoll (String Employee, double salary){

    this.Employee = Employee;
    this.Salary = salary;

}
    public void Employee(String emp){
        Employee = emp;
    }

    public void salary(double slry){
        Salary = slry;
    }

    public void bonus(double bnus){
        bonus = bnus;
    }

    public double totalSalary(double bonus){

        this.bonus = bonus;
        double totalSalary = Salary + bonus;
        this.TotalSalary = totalSalary;
        return totalSalary;
    }

    public void printChart(){

    System.out.println("\nPayRoll");
    System.out.println("-------- EMPLOYEE --------");
    System.out.println("Name:   \t" + Employee);
    System.out.println("Salary: \t" + Salary);
    System.out.println("Bonus:  \t" + bonus);
    System.out.println("Total:  \t" + TotalSalary);
    System.out.println();
    }
}

---

如何打印每个添加的员工？我唯一能想到的是使用arraylist，但我们不允许使用它。

您需要某种数组或集合来存储同一类型的多个实例。在java中使用。作为旁注，我会避免使用Continue作为字符串的名称。continue实际上是Java中用于循环的一个关键字。这本书的底部解释了这一点。