Javascript ajax post请求后作用域变量未更改
我在做一个雅思水疗。这是我的js文件Javascript ajax post请求后作用域变量未更改,javascript,php,ajax,angularjs,laravel,Javascript,Php,Ajax,Angularjs,Laravel,我在做一个雅思水疗。这是我的js文件 var game = angular.module('yahtzee',[]); game.controller('RollDicesController', function($scope, $http) { $scope.img1 = "style/img/dice1.jpg"; $scope.img2 = "style/img/dice2.jpg"; $scope.img3 = "style/img/dice3.jpg"; $scop
var game = angular.module('yahtzee',[]);
game.controller('RollDicesController', function($scope, $http) {
$scope.img1 = "style/img/dice1.jpg";
$scope.img2 = "style/img/dice2.jpg";
$scope.img3 = "style/img/dice3.jpg";
$scope.img4 = "style/img/dice4.jpg";
$scope.img5 = "style/img/dice5.jpg";
$scope.result = {
Ones : '0',
Twos : '0',
Threes : '0',
Fours : '0',
Fives : '0',
Sixes : '0',
ThreeOfAKind : '0',
FourOfAKind : '0',
FullHouse : '0',
SmallStraight : '0',
LargeStraight : '0',
Chance: '0',
Yahtzee : '0'
};
$scope.notSorted = function(obj){
if (!obj) {
return [];
}
return Object.keys(obj);
}
$scope.rollDices = function() {
$dice1 = Math.floor((Math.random() * 6) + 1);
$dice2 = Math.floor((Math.random() * 6) + 1);
$dice3 = Math.floor((Math.random() * 6) + 1);
$dice4 = Math.floor((Math.random() * 6) + 1);
$dice5 = Math.floor((Math.random() * 6) + 1);
$scope.img1 = "style/img/dice" + $dice1 + ".jpg";
$scope.img2 = "style/img/dice" + $dice2 + ".jpg";
$scope.img3 = "style/img/dice" + $dice3 + ".jpg";
$scope.img4 = "style/img/dice" + $dice4 + ".jpg";
$scope.img5 = "style/img/dice" + $dice5 + ".jpg";
$http.post('calculate', {'dice1': $dice1, 'dice2': $dice2, 'dice3': $dice3, 'dice4': $dice4, 'dice5': $dice5 }).success(function(data) {
$scope.result = data;
}).error(function(data, status) {
$scope.errors.push(status);
});
};
});
请求所做的几乎是相应移动的属性值。我有一个php控制器连接到calculate
route(我使用的是Laravel),它完成了所有的数学工作。
现在的问题是,尽管我正确地接收到了值(我已经测试过了),但我的表没有更新
我的网页中已经有一个定义了控制器的主div:
<div ng-controller="RollDicesController">
<div id="game_div">
<div id="dice_div">
<ul>
<li style="list-style-type: none;" class="listaDados" >
<img id="dice1" ng-src="{{img1}}">
<img id="dice2" ng-src="{{img2}}" >
<img id="dice3" ng-src="{{img3}}" >
<img id="dice4" ng-src="{{img4}}" >
<img id="dice5" ng-src="{{img5}}" >
</li>
</ul>
<a>
<button id="rolldice_button" class= "button_class" ng-click="rollDices()">
Roll Dice!
</button>
</a>
<div id="table_div">
<table id="score_table" border="1" >
<tr ng-repeat="key in notSorted(result) track by $index" ng-init="val = result[key]">
<td> {{ key }} </td>
<td> {{ val }} </td>
</tr>
</table>
</div>
</div>
我按下按钮,它工作了一次,而下面的点击并没有改变桌子。
由于某种原因,在我给$scope.result
一个值之后,它的值再也不会改变。由于我对AngularJS的了解有限,我不知道为什么会发生这种情况
编辑2:我尝试使用$scope.apply()更改请求,如下所示
$http.post('calculate', {'dice1': $dice1, 'dice2': $dice2, 'dice3': $dice3, 'dice4': $dice4, 'dice5': $dice5 }).success(function(data) {
$scope.result = data;
$scope.apply();
}).error(function(data, status) {
$scope.errors.push(status);
});
编辑3:$scope.$apply
在我以前的编辑中写得很糟糕,在更正它之后,它现在向我显示了这个错误
错误:错误:inprog
行动已在进行中
$digest已在进行中
最终编辑:$timeout起作用了,问题是使用了notSorted函数
现在创建的表如下所示:
<div id="table_div">
<table id="score_table" border="1" >
<tr ng-repeat="(key, val) in result track by $index">
<td> {{ key }} </td>
<td> {{ val }} </td>
</tr>
</table>
</div>
{{key}}
{{val}}
虽然它没有按照我想要的方式排序,但至少它是有效的 试试这个,建议不要使用$apply 注意,我在顶部插入了$timeout
var game = angular.module('yahtzee',[]);
game.controller('RollDicesController', function($scope, $http, $timeout) {
$scope.img1 = "style/img/dice1.jpg";
$scope.img2 = "style/img/dice2.jpg";
$scope.img3 = "style/img/dice3.jpg";
$scope.img4 = "style/img/dice4.jpg";
$scope.img5 = "style/img/dice5.jpg";
$scope.result = {
Ones : '0',
Twos : '0',
Threes : '0',
Fours : '0',
Fives : '0',
Sixes : '0',
ThreeOfAKind : '0',
FourOfAKind : '0',
FullHouse : '0',
SmallStraight : '0',
LargeStraight : '0',
Chance: '0',
Yahtzee : '0'
};
$scope.notSorted = function(obj){
if (!obj) {
return [];
}
return Object.keys(obj);
}
$scope.rollDices = function() {
$dice1 = Math.floor((Math.random() * 6) + 1);
$dice2 = Math.floor((Math.random() * 6) + 1);
$dice3 = Math.floor((Math.random() * 6) + 1);
$dice4 = Math.floor((Math.random() * 6) + 1);
$dice5 = Math.floor((Math.random() * 6) + 1);
$scope.img1 = "style/img/dice" + $dice1 + ".jpg";
$scope.img2 = "style/img/dice" + $dice2 + ".jpg";
$scope.img3 = "style/img/dice" + $dice3 + ".jpg";
$scope.img4 = "style/img/dice" + $dice4 + ".jpg";
$scope.img5 = "style/img/dice" + $dice5 + ".jpg";
$http.post('calculate', {'dice1': $dice1, 'dice2': $dice2, 'dice3': $dice3, 'dice4': $dice4, 'dice5': $dice5 }).success(function(data) {
$timeout(function() {
$scope.result = data;
});
}).error(function(data, status) {
$scope.errors.push(status);
});
};
});
请尝试以下代码:
<div id="table_div">
<table id="score_table" border="1" >
<tr ng-repeat="key in result track by $index" ng-init="val = result[key]">
<td> {{ key }} </td>
<td> {{ val }} </td>
</tr>
</table>
</div>
为什么需要
notSorted()
函数?在ajax调用中使用承诺,并将结果模型附加到repeater@LozCheroneツ 你能举个例子说明怎么做吗?我是个新手AngularJS@LozCheroneツ 我找到了另一种对表进行排序的方法,它说$timeout没有定义。您是否将它注入控制器定义中?请参阅game.controller('rolldiescocontroller',function($scope,$http,$timeout){。您需要像我在代码中做的那样将它放在那里。哦,对不起,我现在才注意到它。我会这样做。这没有任何意义,我需要notSorted函数才能按我想要的顺序排列数组,然后尝试上面给出的第二个选项。
<div id="table_div">
<table id="score_table" border="1" >
<tr ng-repeat="key in result track by $index" ng-init="val = result[key]">
<td> {{ key }} </td>
<td> {{ val }} </td>
</tr>
</table>
</div>
$http.post('calculate', {'dice1': $dice1, 'dice2': $dice2, 'dice3': $dice3, 'dice4': $dice4, 'dice5': $dice5 }).success(function(data) {
$timeout(function() {
$scope.result = data;
});
}).error(function(data, status) {
$scope.errors.push(status);
});
$timeout to avoid $digest error.