返回基于父过滤器的Javascript子数组

免责声明：我了解一些Java，但对Javascript几乎一无所知，并且有大约2天的时间来解决其他人的问题，这只是其中的一小部分

我有一个嵌套数组。我知道店号，但只需要获得该店零件的阵列

"shops": [
    {
      "shopID": "15231",
      "city": "Anytown",
      "state": "MO",
      "inventory": [
        {
          "description": "filter",
          "partnumber": "MGL57047",
          "shelf": "Z",
        },
        {
          "description": "filter",
          "partnumber": "84060",
          "shelf": "A",
        }
    },
    {
      "shopID": "15232",
      "city": "Springfield",
      "state": "IL",
      "inventory": [
        {
          "description": "filter",
          "partnumber": "MGL57048",
          "shelf": "B",
        },
        {
          "description": "filter",
          "partnumber": "84061",
          "shelf": "A",
        }
    }

以下是我尝试过的：

const enteredShopID = '15231' // This isn't hard-coded in my app.
// Pull the list of all consumables for the current shop
var currentShop = application.data.shops.filter(s => s.shopID == enteredShopID)

这会给我一个包含商店和该商店所有库存的数组，但我需要一个库存数组。我试过了

var currentShop = application.data.shops.inventory.filter(s => s.shopID == enteredShopID)

但那没用。真的，我只是在这里摸索。有没有办法使后一条语句起作用，并以某种方式引用父项的shopID？

只需在筛选后使用

map（）

var currentShop = application.data.shops
   .filter(s => s.shopID == enteredShopID)[0]

// checking if the current shop is actually null because no shops matched the ID
var currentShopInventory = (currentShop || {}).inventory || []

或者使用

find（）

---

如果ID是唯一的，那么它应该是

.find（）

，而不是

.filter（）

！第一个建议奏效了！

// Note: If you use find(), there's a chance that there is no matching object
// So you'll have to check for that before you access the "inventory" key
// Otherwise you'll get "Cannot access 'inventory' of null"
var matchingShop = application.data.shops
   .find(s => s.shopID == enteredShopID)

// Doing the checking here using an "or" if the matchingShop is null
var currentShop = matchingShop || {}
var currentShopInventory = currentShop.inventory || []