Javascript 从流媒体音频功能更新useState时无限重渲染

我正在构建一个应用程序React Native，将一系列音频文件发送到Expo AV audio.Sound对象中，加载并播放它们，然后尝试使用正在播放的音频文件的信息更新应用程序本身的显示，特别是用户通过文件的距离。我试图通过useState钩子更新显示，该钩子由音频播放器的回调函数调用

我遇到的问题是，每当我试图更改音频播放器回调函数的状态时，就会被抛出无限重渲染。简化代码如下：

import React, { useState} from 'react';
import { Audio } from 'expo-av';

const AudioPlayer = ({ user }) => {
    const [currentProgress, setCurrentProgress] = useState(0);

    const soundObject = new Audio.Sound();
    soundObject.setOnPlaybackStatusUpdate(playbackUpdate);
    // sets a function that is called every 500 milliseconds as the audio is played 

    if(user) {
          soundObject.loadAsync({user.message.path});
    }

    const play = () => {
          soundObject.playAsync();
    }

    const playbackUpdate = (playbackObject) => {
          setCurrentProgress(playbackObject.currentMillis);
          // updating state with progress through audio file in milliseconds
    }

    return (
          <View>
             <Text>{currentProgress}</Text>
             <Button title="play" onPress={play} />
          </View>
    )

}

export default AudioPlayer

---

请记住，函数体中的所有内容都将在每个渲染上运行，因此在本例中，您将创建一个新的soundObject，并可能在每个渲染上运行soundObject.loadAsync调用。您需要利用其他钩子来避免这种情况——在您的情况下可能是useRef和useffect。我建议通过hooks api参考来熟悉这些：

下面是一个如何避免不必要影响的快速尝试。您可能需要查看和调整依赖项数组，具体取决于您希望如何运行以及何时重新运行各种效果。例如，我不确定是否需要重新创建声音对象

import React, { useState, useRef, useCallback, useEffect} from 'react';
import { Audio } from 'expo-av';
import { Button, View, Text } from 'react-native';

const AudioPlayer = ({ user }) => {
    const [currentProgress, setCurrentProgress] = useState(0);

    const soundObjectRef = useRef(new Audio.Sound());

    useEffect(() => {

      const playbackUpdate = (playbackObject) => {
          setCurrentProgress(playbackObject.currentMillis);
          // updating state with progress through audio file in milliseconds
      }
      soundObjectRef.current.setOnPlaybackStatusUpdate(playbackUpdate);
    }, []); // do this only once per component mount
    // sets a function that is called every 500 milliseconds as the audio is played 

    useEffect(() => {
      if (user) {
        soundObjectRef.current.loadAsync({user.message.path});
      }
    }, [user]); // run this anytime user changes but do not run again if user doesn't change

    const play = () => {
          soundObjectRef.current.playAsync();
    }

    return (
          <View>
             <Text>{currentProgress}</Text>
             <Button title="play" onPress={play} />
          </View>
    )

}

export default AudioPlayer

---

请记住，函数体中的所有内容都将在每个渲染上运行，因此在本例中，您将创建一个新的soundObject，并可能在每个渲染上运行soundObject.loadAsync调用。您需要利用其他钩子来避免这种情况——在您的情况下可能是useRef和useffect。我建议通过hooks api参考来熟悉这些：

下面是一个如何避免不必要影响的快速尝试。您可能需要查看和调整依赖项数组，具体取决于您希望如何运行以及何时重新运行各种效果。例如，我不确定是否需要重新创建声音对象

import React, { useState, useRef, useCallback, useEffect} from 'react';
import { Audio } from 'expo-av';
import { Button, View, Text } from 'react-native';

const AudioPlayer = ({ user }) => {
    const [currentProgress, setCurrentProgress] = useState(0);

    const soundObjectRef = useRef(new Audio.Sound());

    useEffect(() => {

      const playbackUpdate = (playbackObject) => {
          setCurrentProgress(playbackObject.currentMillis);
          // updating state with progress through audio file in milliseconds
      }
      soundObjectRef.current.setOnPlaybackStatusUpdate(playbackUpdate);
    }, []); // do this only once per component mount
    // sets a function that is called every 500 milliseconds as the audio is played 

    useEffect(() => {
      if (user) {
        soundObjectRef.current.loadAsync({user.message.path});
      }
    }, [user]); // run this anytime user changes but do not run again if user doesn't change

    const play = () => {
          soundObjectRef.current.playAsync();
    }

    return (
          <View>
             <Text>{currentProgress}</Text>
             <Button title="play" onPress={play} />
          </View>
    )

}

export default AudioPlayer

---

非常感谢你的回答，阅读你发布的链接，这看起来正是我需要的。今天晚些时候将尝试实现它。再次感谢您的帮助，在经过一点黑客攻击之后，您的建议使它能够正常工作。谢谢非常感谢你的回答，阅读你发布的链接，这看起来正是我需要的。今天晚些时候将尝试实现它。再次感谢您的帮助，在经过一点黑客攻击之后，您的建议使它能够正常工作。谢谢