Javascript json eval给出了一个错误

我对下面的JSON使用eval，但得到语法错误：应为']'消息。我没有得到我所缺少的东西。 我的javascript stmt是

eval('var jsonResponse = ('+response+')');  

答复包括以下内容：

{iserror:"false",employees:["employee":{"employeeNbr":"SAN1234509","emplType":"SAN","agencyNbr":"","producerNbr":"123456789","remiCode":"SA","agentRate":"SA","typeCode":"I","reasonTxt":"S3","rsnDescription":"null","ymdeff":"20130101","ymdend":"20130101","voidtxt":"V","brokerName":"429610583","brokerNpn":"429610583","ymdtrans":"null","opNbr":"null"},
                            "employee":{"employeeNbr":"SAN1234509","emplType":"SAN","agencyNbr":"xxxxx-C","producerNbr":"1234567890,"remiCode":"SA","agentRate":"SA","typeCode":"I","reasonTxt":"S3","rsnDescription":"null","ymdeff":"20130101","ymdend":"20130101","voidtxt":"","brokerName":"429610583","brokerNpn":"429610583","ymdtrans":"null","opNbr":"null"},
                            "employee":{"employeeNbr":"SAN1234509","emplType":"SAN","agencyNbr":"","producerNbr":"123456789","remiCode":"SA","agentRate":"SA","typeCode":"I","reasonTxt":"S3","rsnDescription":"null","ymdeff":"20130101","ymdend":"20130101","voidtxt":"V","brokerName":"429610583","brokerNpn":"429610583","ymdtrans":"null","opNbr":"null"}]}

---

首先，您声称它是JSON，但事实并非如此。例如，

iserror

周围需要引号才能成为JSON

具体来说,

{iserror:"false",employees:[...]}

应该是

{"iserror":"false","employees":[...]}

---

但是，因为您实际上将字符串传递给JavaScript解析器（eval），所以它只需要是JavaScript，而不是JSON。它也不是有效的JavaScript，这就是为什么会出现错误

你有

{
   iserror:"false",
   employees:[
      "employee":{...},
      "employee":{...},
      "employee":{...}
   ]
}

“员工”

之后的

：

是错误的。也许你想用

{
   iserror:"false",
   employees:[
      {...},
      {...},
      {...}
   ]
}

---

还有，你有

"producerNbr":"1234567890,"remiCode":"SA"

而不是

"producerNbr":"1234567890","remiCode":"SA"

---

如果只看语法突出显示，您会注意到，这不是有效的代码。一般来说，尝试使用

JSON.parse（）

执行此类任务，但您的数据必须是“真实”的JSON。这不是JSON。例如，

iError

周围需要引号才能成为JSON，JSLint讨厌那里的对象……我会去查看它以查看所有错误：www.JSLint.com

，“

应该是

”，

在

producerNbr的第二行：

：“1234567890”，remiCode“：另外，不要自己创建/解析JSON，请使用@VisioN之类的序列化程序。